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我正在尝试在服务器上压缩多个文件并在用户请求时下载它。我正在使用 adm-zip 压缩文件。

文件添加得非常好并且被压缩。zip.writeZip('') 完美地压缩文件并将它们保存到本地服务器。我只是无法下载它们。无论哪种方式,我认为如果我可以直接通过缓冲区发送 zip 会更好。

router.get(
  "/download-zip/:season_id/:club_id",
  passport.authenticate("jwt", { session: false }),
  (req, res) => {
    FileSubmission.find({
      season: req.params.season_id,
      club: req.params.club_id
    }).then(files => {

      const zip = new AdmZip();

      files.forEach(file => {
        // add local file
        zip.addLocalFile(`uploads/club-uploads/${file.club}/${file.name}`);
      });

      res.download(zip.toBuffer(), "asd.zip");
    });
  }
);

在前面,我正在使用对动作和 js-file-download 库做出反应


// Download ALL FILES by season ID and club ID
import fileDownload from "js-file-download";

export const downloadAllFiles = (season_id, club_id) => dispatch => {
  axios
    .get(`/api/files/download-zip/${season_id}/${club_id}`)
    .then(response => {
      fileDownload(response.data, `All Files- ${club_id}.zip`);
    })
    .catch(err => {
      console.log(err);
      dispatch({ type: GET_ERRORS, payload: err.response.data });
    });
};
4

1 回答 1

0

这是我设法创建临时存档,下载并删除它的方法。

这里是后端

// Create a ZIP of files uploaded by a club
router.get(
  "/download-zip/",
  (req, res) => {
      zip.addLocalFile(/*ADD THE FILES TO ZIP*/);

      zip.writeZip(
        `temp/zips/temp-file.zip`,
        err => {
          if (err) {
            console.log(err);
          }

          res.download(
            `uploads/club-zips/test-file.zip`,
            function(err) {
              if (!err) {
                //delete file after it's been downloaded
                fs.unlinkSync(
                  `uploads/club-zips/test-file-${req.params.club_id}.zip`
                );
              }
            }
          );
        }
      );
    });
  }
);

这是我在前面使用的。正如我所说,我使用名为 js-file-download 的包来下载 blob

export const downloadAllFiles = () => dispatch => {
  axios
    .get(`/api/files/download-zip/`, {
      responseType: "arraybuffer"
    })
    .then(response => {
      fileDownload(response.data, `all-files.zip`);
    })
    .catch(err => {
      console.log(err);
    });
};
于 2019-10-16T09:03:03.857 回答