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我正在使用urllibinpython3从我的服务器获取一些图像：

import urllib.request
import urllib.error
        try:
            resp = urllib.request.urlopen(url)
        except urllib.error.HTTPError as err:
            print("code "  + str(err.status) + " reason " + err.reason)

运行该文件会输出 410 HTTP Gone 错误，

 $ python3.6 file.py 

download: http://some_url.com/image.jpg
code 410 reason Gone

Traceback (most recent call last):
  File "file.py", line 32, in <module>
    image = image_from_url(url)

但我确定图像在那里，因为wget返回图像很好：

$ wget http://some_url.com/image.jpg

--2019-10-11 16:24:05--  http://some_url.com/image.jpg
Resolving some_url.com...
Connecting to some_url.com|...|:80... connected.
HTTP request sent, awaiting response... 200 OK
Length: 127891 (125K) [image/jpeg]
Saving to: 'image.jpg'

关于造成这种情况的任何想法？服务器端的东西？urllib 请求中是否有一些特定的标头？

谢谢

4

1 回答 1

1

urllib要求：

GET /wikipedia/commons/c/c9/Moon.jpg HTTP/1.1
Accept-Encoding: identity
Host: upload.wikimedia.org
User-Agent: Python-urllib/3.6
Connection: close

wget要求：

GET /wikipedia/commons/c/c9/Moon.jpg HTTP/1.1
User-Agent: Wget/1.19.4 (linux-gnu)
Accept: */*
Accept-Encoding: identity
Host: upload.wikimedia.org
Connection: Keep-Alive

尝试添加Accept: */*标题？一些研究表明，过滤掉缺少此标头的请求是一种常见的做法，因为它们通常是机器人。

req = urllib.request.Request('some_url', headers = {'Accept': '*/*'})
resp = urllib.request.urlopen(req)
于 2019-10-11T16:32:19.383 回答