3
item = Table('Item', metadata, autoload=True, autoload_with=engine, encoding = 'cp1257')

class Item(object):
    pass

from sqlalchemy.orm import mapper
mapper(Item, item)

我得到错误:

line 43, in <module>
    mapper(Item, item) 
  File "C:\Python27\lib\site-packages\sqlalchemy\orm\__init__.py", line 890, in mapper
    return Mapper(class_, local_table, *args, **params)
  File "C:\Python27\lib\site-packages\sqlalchemy\orm\mapper.py", line 211, in __init__
    self._configure_properties()
  File "C:\Python27\lib\site-packages\sqlalchemy\orm\mapper.py", line 578, in _configure_properties
    setparent=True)
  File "C:\Python27\lib\site-packages\sqlalchemy\orm\mapper.py", line 618, in _configure_property
    self._log("_configure_property(%s, %s)", key, prop.__class__.__name__)
  File "C:\Python27\lib\site-packages\sqlalchemy\orm\mapper.py", line 877, in _log
    (self.non_primary and "|non-primary" or "") + ") " + 
  File "C:\Python27\lib\site-packages\sqlalchemy\util.py", line 1510, in __get__
    obj.__dict__[self.__name__] = result = self.fget(obj)
  File "C:\Python27\lib\site-packages\sqlalchemy\sql\expression.py", line 3544, in description
    return self.name.encode('ascii', 'backslashreplace')
UnicodeDecodeError: 'ascii' codec can't decode byte 0xeb in position 7: ordinal not in range(128)

我正在连接到 MSSQL。表自动加载似乎工作。我只在尝试映射时收到此错误。谢谢大家的帮助!

4

3 回答 3

3

将表映射到类会在类上创建映射属性。默认情况下,属性具有与列相同的名称。由于 python 2.x 仅允许 ascii 标识符,因此如果您有非 ascii 列名,则会失败。

我能想到的唯一解决方案是在将表映射到类时给标识符一个不同的名称。

下面的例子就是这样做的。请注意,为了简单起见,我在代码上创建了表格,因此任何人都可以在没有现有表格的情况下运行代码。但是你可以对反射表做同样的事情。

#-*- coding:utf-8 -*-

import sqlalchemy as sa
import sqlalchemy.orm

engine = sa.create_engine('sqlite://', echo=True) # new memory-only database
metadata = sa.MetaData(bind=engine)

# create a table. This could be reflected from the database instead:
tb = sa.Table('foo', metadata, 
    sa.Column(u'id', sa.Integer, primary_key=True),
    sa.Column(u'nomé', sa.Unicode(100)),
    sa.Column(u'ãéìöû', sa.Unicode(100))
)    
tb.create()

class Foo(object):
    pass

# maps the table to the class, defining different property names 
# for some columns:
sa.orm.mapper(Foo, tb, properties={
    'nome': tb.c[u'nomé'],
    'aeiou': tb.c[u'ãéìöû']
})

之后,您可以使用Foo.nome来引用nomé列和Foo.aeiou引用ãéìöû列。

于 2011-04-29T12:30:04.987 回答
1

我遇到了同样的问题,最后设法在自动加载后替换 table['column'].key ,只需让所有表类继承这个,然后在 mapTo 方法中修改列名替换或手动覆盖所需的名称字典和 columns_descriptor 方法。我不知道这是否不是正确的方法,但经过几个小时的搜索是我所拥有的最佳方法。

class SageProxy(object):

@classmethod
def ismapped(cls, table_name=None):
    if mappings:
        if table_name:
            if mappings.has_key(table_name):
                tmap=mappings[table_name]
                if tmap.has_key('class'):
                    tclass=tmap['class']
                    if tclass is cls:
                        return True
        else:
            for m in mappings:
                if cls is m['class']:
                    return True
    return False

@classmethod
def mappingprops(cls):
    #override this to pass properties to sqlalchemy mapper function
    return None

@classmethod
def columns_descriptors(cls):
    #override this to map columns to different class properties names
    #return dictionary where key is the column name and value is the desired property name
    return {}

@classmethod
def mapTo(cls, table_name, map_opts=None):
    if not cls.ismapped(table_name):
        tab_obj=Table(table_name,sage_md,autoload=True)
        for c in tab_obj.c:
            #clean field names
            tab_obj.c[c.name].key=c.key.replace(u'%',u'Porcentaje').replace(u'ñ',u'ny').replace(u'Ñ',u'NY').replace(u'-',u'_') 
        for k,v in cls.columns_descriptors():
            if tab_obj.c[k]:
                tab_obj.c[k].key=v
        mapper(cls, tab_obj, properties=cls.mappingprops())
        mappings[table_name]={'table':tab_obj,'class':cls}
    return cls

我希望它会很有用

于 2011-11-17T02:56:25.580 回答
1

我发现我可以通过对反射类的简单添加来做到这一点:

metadata = MetaData(bind=engine, reflect=True)
sm = sessionmaker(bind=engine)

class tblOrders(Base):
    __table__ = metadata.tables['tblOrders']
    meter = __table__.c['Meter#']

meter现在映射到基础Meter#列,这允许此代码工作:

currOrder = tblOrders()
currOrder.meter = '5'

如果没有映射,python 将其视为一个损坏的语句Meter,因为对象中不存在后跟注释。

于 2012-02-24T16:21:56.613 回答