1

这是与以下相同的问题，但不同之处在于我使用的是 docplex。

cplex.linear_constraints.add 对于大型模型来说太慢了

如何使用带有 docplex 的索引添加约束？

我的代码如下所示。

x = lm.binary_var_dict(range(n),name="x");
xv = [ax for i,ax in x.items()];

for i in range(l):
  Bx = {xv[j]:B[i,j] for j in range(n)};
  Bx = lm.linear_expr(Bx);
  lm.add_constraint(Bx == 1);
4

2 回答 2

1

您可以尝试批量添加约束吗？

使用 Model.add_constraints() 为模型批量添加约束通常更有效。尝试在列表或理解中对约束进行分组（两者都有效）。

例子：

m.add_constraints((m.dotf(ys, lambda j_: i + (i+j_) % 3) >= i for i in rsize),
         ("ct_%d" % i for i in rsize))

从编写高效的 DOcplex 代码

于 2019-10-10T06:05:20.333 回答
0

有许多替代方法可以创建约束。例如，您可以使用函数sum或scal_prod. 您可以批量创建或不批量创建。这是一个小测试代码，说明了不同的变体：

from docplex.mp.model import Model
import time

n = 1000
l = n
B = { (i, j) : i * n + j for i in range(l) for j in range(n) }
with Model() as m:
    x = m.binary_var_dict(range(n),name="x");
    xv = [ax for i,ax in x.items()];

    start = time.time()
    for i in range(l):
        Bx = {xv[j]:B[i,j] for j in range(n)};
        Bx = m.linear_expr(Bx);
        m.add_constraint(Bx == 1);
    elapsed1 = time.time() - start
print('Original: %.2f' % elapsed1)

with Model() as m:
    x = m.binary_var_dict(range(n),name="x");
    xv = [ax for i,ax in x.items()];

    start = time.time()
    m.add_constraints(m.linear_expr({xv[j]:B[i,j] for j in range(n)}) == 1 for i in range(l))
    elapsed2 = time.time() - start
print('Original batched: %.2f' % elapsed2)

with Model() as m:
    x = m.binary_var_dict(range(n),name="x");
    xv = [ax for i,ax in x.items()];

    start = time.time()
    for i in range(l):
        m.add_constraint(m.sum(B[i,j] * xv[j] for j in range(n)) == 1)
    elapsed3 = time.time() - start
print('Sum: %.2f' % elapsed3)

with Model() as m:
    x = m.binary_var_dict(range(n),name="x");
    xv = [ax for i,ax in x.items()];

    start = time.time()
    Bx = m.linear_expr(Bx);
    m.add_constraints(m.sum(B[i,j] * xv[j] for j in range(n)) == 1 for i in range(l))
    elapsed4 = time.time() - start
print('Sum batched: %.2f' % elapsed4)

with Model() as m:
    x = m.binary_var_dict(range(n),name="x");
    xv = [ax for i,ax in x.items()];

    start = time.time()
    for i in range(l):
        m.add_constraint(m.scal_prod([xv[j] for j in range(n)],
                                     [B[i,j] for j in range(n)]) == 1)
    elapsed5 = time.time() - start
print('scal_prod: %.2f' % elapsed5)

with Model() as m:
    x = m.binary_var_dict(range(n),name="x");
    xv = [ax for i,ax in x.items()];

    start = time.time()
    Bx = m.linear_expr(Bx);
    m.add_constraints(m.scal_prod([xv[j] for j in range(n)],
                                  [B[i,j]for j in range(n)]) == 1 for i in range(l))
    elapsed6 = time.time() - start
print('scal_prod batched: %.2f' % elapsed6)

在我的盒子上，这给了

Original: 1.86
Original batched: 1.82
Sum: 2.84
Sum batched: 2.81
scal_prod: 1.55
scal_prod batched: 1.50

所以批处理不会买太多但scal_prod比linear_expr

于 2019-10-10T07:29:59.227 回答