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我想将 JSON 对象传递给 SQL Server 2016 存储过程，而不反序列化对象并让数据库处理数据。

我传入：

DECLARE @json NVarChar(2048) = N'[{
    "PMID": "31390573",
    "pubdate": "2019",
    "data": {
        "memberID": "1692",
        "pmid": "31390573",     
        "sortpubdate": "2019/08/06 00:00",
        "pmc": "PMC6733019"
    }
}, {
    "PMID": "31213464",
    "pubdate": "2019",
    "data": {
        "memberID": "1692",
        "pmid": "31213464",     
        "sortpubdate": "2019/08/15 00:00",
        "pmc": "PMC6753942"
    }
}, {
    "PMID": "31130363",
    "pubdate": "2019",
    "data": {
        "memberID": "1692",
        "pmid": "31130363",     
        "sortpubdate": "2019/06/20 00:00",
        "pmc": "PMC6588466"
    }
}]'

如果我使用

SELECT * FROM OPENJSON(@json);

我明白了

0   {   "PMID": "31390573",   "pubdate": "2019",   "data": {    "memberID": "1692",    "pmid": "31390573",      "sortpubdate": "2019/08/06 00:00",    "pmc": "PMC6733019"   }  }    5
1   {   "PMID": "31213464",   "pubdate": "2019",   "data": {    "memberID": "1692",    "pmid": "31213464",      "sortpubdate": "2019/08/15 00:00",    "pmc": "PMC6753942"   }  }    5
2   {   "PMID": "31130363",   "pubdate": "2019",   "data": {    "memberID": "1692",    "pmid": "31130363",      "sortpubdate": "2019/06/20 00:00",    "pmc": "PMC6588466"   }  }    5

我想最终得到一个表，其中一列用于数据元素中的项目，因此一列用于 memberID -- pmid --sortpubdate--pmc。

memberID    pmid        sortpubdate
------------------------------------------------
1692        31390573    2019-08-06 00:00:00.0000000
1692        31213464    2019-08-15 00:00:00.0000000
1692        31130363    2019-06-20 00:00:00.0000000

这可能吗？如果它是 XML，它可以被撕开和处理。

4

1 回答 1

0

我找到了答案，我会把它留在这里以防其他人需要它

SELECT *  
FROM OPENJSON(@json)  
  WITH ( 
        memberID int '$.data.memberID', pmid int '$.data.pmid',  
         sortpubdate datetime2 '$.data.sortpubdate') 
END
于 2019-10-04T02:23:12.643 回答