我正在尝试创建一个简单的选择器来通过 a 获取商店中的所有消息visitor_id
,但是,看起来如此简单的事情在 ngrx 中实现总是具有挑战性。
我正在使用ngrx实体,所以我已经selectAll
准备好选择器,所以我尝试执行以下操作:
export const selectMessagesState = createFeatureSelector<MessagesState>('messages');
export const selectAllMessages = createSelector(
selectMessagesState,
fromMessage.selectAll
);
export const selectMessageByVisitorId = createSelector(
select(selectAll),
(visitor_id) => map(val => val.filter(c => c.visitor_id == visitor_id))
);
在组件中:
export class Message {
id: number;
message: string;
visitor_id: number;
is_from_visitor: boolean;
created_at: string;
}
public messages$ : Observable<Message[]>;
public showThread(visitor: Visitor){
this.messages$ = this.store.select(selectMessageByVisitorId({ visitor_id: visitor.id}));
不过我要Property 'filter' does not exist on type 'unknown'
进去了selectMessageByVisitorId
。我很确定我没有遵循正确的方法。我要做的很简单,将 a 传递visitor id
给选择selectMessageByVisitorId
器,它会返回特征存储中的消息列表,由visitor_id
.
更新#1
根据@Nikhil 的建议,我将选择器更改为:
export const selectMessageByVisitorId = ({visitor_id}) => createSelector(
select(selectAll),
messages => messages.filter(val => val.visitor_id == visitor_id)
);
但是我得到了Property 'filter' does not exist on type 'Observable<Message[]>
,虽然我导入了事件import { filter} from 'rxjs/operators';
(我使用 ngrx 8.0)。
所以我想尝试:
export const selectMessageByVisitorId = ({visitor_id}) => createSelector(
select(selectAll),
messages => messages.pipe(
map(val => val.filter(c => c.visitor_id == visitor_id) )
)
);
但现在我进入Type 'Observable<Observable<Message[]>>' is not assignable to type 'Observable<Message[]>'.
了组件文件this.messages$ = this.store.select(selectMessageByVisitorId({ visitor_id: visitor.id}));