graphql - 如何在 Graphql Ruby 中接受嵌套查询的字段参数？

Question

我在 GraphQl（Apollo JS/Graphql Ruby）中遇到了这个错误： Error Error: GraphQL error: Field 'pagination' doesn't accept argument 'pagination' GraphQL error: Variable $pagination is declared by Clients but not used. Reload the page and try again.

我有这个查询：

query Clients($pagination: PaginationInput) {
  clients {
     data {
       ....Fragment
     }
     pagination(pagination: $pagination) {
       ....Fragment
     }

  }
}

我有这个作为我的输入类型：

class PaginatedClientsType < Types::BaseObject
   field :data, ...
   field :pagination, PaginationType ... do 
     argument :pagination, PaginationInput, required: false
   end
end

这在我的query_type.rb文件中：

field :clients, ::Types::Paginated::ClientsType, null: false do
   argument :pagination, PaginationInput, required: false
end

def clients(pagination:)
  ...
end

// and i've added to no avail:
field :pagination ... do
   argument :pagination, PaginationInput, required: false
end
def pagination(pagination:)
...
end

关于如何将论点传递给此顶层以外的其他东西的任何想法client？我在这里阅读过文档，但无法弄清楚。

谢谢！