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我在需要运行旧版 32 位报告应用程序的 64 位计算机上有一个 ASP .NET Web 应用程序。

当我使用 运行程序时UseShellExecute = false，程序以退出代码退出：

-1073741502

我不能使用 Shell Execute，因为我必须以不同的用户身份运行该进程。然而，当 Shell Execute 为真时，该进程将运行良好（尽管我必须更改执行 ASP .NET 的用户）。

如何在不使用 shell 执行的情况下使用 C# 启动这个 32 位程序？

这是我现在拥有的代码：

var pxs = new ProcessStartInfo
{
    Arguments = arguments,
    CreateNoWindow = true,
    Domain = ConfigurationManager.AppSettings["reportUserDomain"],
    UserName = ConfigurationManager.AppSettings["reportUserName"],
    Password = GetSecureString(ConfigurationManager.AppSettings["reportUserPassword"]),
    LoadUserProfile = true,
    FileName = ConfigurationManager.AppSettings["reportRuntime"],
    UseShellExecute = false             

};

var px = new Process
{
    StartInfo = pxs
};

px.Start();
px.WaitForExit();
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1 回答 1

3

如果您UseShellExecute = true使用 Windows 本机“LogonUser”方法包围您的代码，包括 . 我已经在几个项目中成功地使用它来做类似的事情。

[DllImport("advapi32.dll", CharSet = CharSet.Auto)]
public static extern bool LogonUser(String lpszUserName, String lpszDomain,
    String lpszPassword, int dwLogonType, int dwLogonProvider, ref IntPtr phToken

Fresh Click Media 对此做了一篇文章并写了一个示例模拟类：--> http://www.freshclickmedia.com/blog/2008/11/programmatic-impersonation-in-c/

但为了完整起见，这是我的版本：

public class Impersonator : IDisposable
{
    private WindowsImpersonationContext _impersonatedUser = null;
    private IntPtr _userHandle;

    // constructor for a local account. username and password are arguments.
    public Impersonator(string username, string passwd)
    {
        _userHandle = new IntPtr(0);

        string user = username;
        string userDomain = "."; // The domain for a local user is by default "."
        string password = passwd;

        bool returnValue = LogonUser(user, userDomain, password, LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, ref _userHandle);

        if (!returnValue)
            throw new ApplicationException("Could not impersonate user");

        WindowsIdentity newId = new WindowsIdentity(_userHandle);
        _impersonatedUser = newId.Impersonate();
    }

    // constructor where username, password and domain are passed as parameters
    public Impersonator(string username, string passwd, string domain)
    {
        _userHandle = new IntPtr(0);

        string user = username;
        string userDomain = domain;
        string password = passwd;

        bool returnValue = LogonUser(user, userDomain, password, LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, ref _userHandle);

        if (!returnValue)
            throw new ApplicationException("Could not impersonate user");

        WindowsIdentity newId = new WindowsIdentity(_userHandle);
        _impersonatedUser = newId.Impersonate();
    }

    public void Dispose()
    {
        if (_impersonatedUser != null)
        {
            _impersonatedUser.Undo();
            CloseHandle(_userHandle);
        }
    }

    public const int LOGON32_LOGON_INTERACTIVE = 2;
    public const int LOGON32_LOGON_SERVICE = 3;
    public const int LOGON32_PROVIDER_DEFAULT = 0;

    [DllImport("advapi32.dll", CharSet = CharSet.Auto)]
    public static extern bool LogonUser(String lpszUserName, String lpszDomain, String lpszPassword, int dwLogonType, int dwLogonProvider, ref IntPtr phToken);

    [DllImport("kernel32.dll", CharSet = CharSet.Auto)]
    public extern static bool CloseHandle(IntPtr handle);
}

在您的情况下使用它是：

var domain = ConfigurationManager.AppSettings["reportUserDomain"];
var username = ConfigurationManager.AppSettings["reportUserName"];
var password = ConfigurationManager.AppSettings["reportUserPassword"];

using (Impersonator impersonator = new Impersonator(username, password, domain))
{
    var pxs = new ProcessStartInfo
    {
        Arguments = arguments,
        CreateNoWindow = true,
        LoadUserProfile = true,
        FileName = ConfigurationManager.AppSettings["reportRuntime"],
        UseShellExecute = true
    };

    var px = new Process
    {
        StartInfo = pxs
    };

    px.Start();
    px.WaitForExit();
}
于 2011-04-28T01:38:11.173 回答