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如果值不存在，试图弄清楚如何添加 MSSQL-Null 值。

到目前为止，这有效，它将插入新行，如果匹配，它将更新列。但是，如果没有指定终止日期，而不是在数据库中分配一个空值，它将写入 1900-01-01 并且文本字段将为空白而不是空。

尝试添加 +[DBNull]::Value 但没有做任何更改。有点没主意了。:)

用户.CSV：

id,firstname,lastname,middlename,terminationdate
1,A,B,,
2,C,D,E,2019-10-12
3,F,G,,2019-11-12
4,H,I,J,
5,K,,,

$users=Import-csv C:\temp\users.csv

$SQLServer = "localhost\DB"
$SQLDBName = "UDB"
$SQLTableName="dbo.users"

$SQLConn = New-Object System.Data.SQLClient.SQLConnection
$SQLCmd = New-Object System.Data.SQLClient.SQLCommand

$SQLConn.ConnectionString = "Server=$SQLServer;Database=$SQLDBName; Integrated Security= True"
$SQLConn.Open()

$SQLCmd = New-Object System.Data.SqlClient.SqlCommand
$SQLCmd.Connection = $SQLConn

foreach ($user in $users){

#declare the variables
$id = $user.id
$first_name = $user.fname
$last_name = $user.lastname
$middle_name = $user.middlename
$termination_date = $user.terminationdate

$SQLCmd.CommandText = "
IF EXISTS (SELECT * FROM $SQLTableName WHERE id = '$id')
BEGIN
    UPDATE
        $SQLTableName
    SET
    first_name = '$firstname',
    last_name = '$lastname',
    middle_name = '$middlename',
    date_termination = '$terminationdate',
    WHERE
        id = $ID 
END
ELSE
BEGIN
    INSERT INTO 
    $SQLTableName(
    id,
    first_name,
    last_name,
    middle_name,
    termination_date)
    VALUES
    ('$id',       
    '$firstname',
    '$lastname',
    '$middlename',
    '$terminationdate')      
    END"

$SQLCmd.ExecuteNonQuery()
4

2 回答 2

0

好的，我想我现在明白了：）

$users=Import-csv C:\temp\users.csv

$SQLServer = "localhost\DB"
$SQLDBName = "UDB"
$SQLTableName="dbo.users"

$SQLConn = New-Object System.Data.SQLClient.SQLConnection
$SQLCmd = New-Object System.Data.SQLClient.SQLCommand

$SQLConn.ConnectionString = "Server=$SQLServer;Database=$SQLDBName; Integrated Security= True"
$SQLConn.Open()

$SQLCmd = New-Object System.Data.SqlClient.SqlCommand
$SQLCmd.Connection = $SQLConn

foreach ($user in $users){
$SqlCmd.Parameters.Clear()

$SQLCmd.CommandText = "
IF EXISTS (SELECT * FROM $SQLTableName WHERE id = @id)
BEGIN
    UPDATE
        $SQLTableName
    SET
    first_name = @firstname,
    last_name = @lastname,
    middle_name = @middlename,
    termination_date = @terminationdate,
    WHERE
        id = @id 
END
ELSE
BEGIN
    INSERT INTO 
    $SQLTableName(
    id,
    first_name,
    last_name,
    middle_name,
    termination_date)
    VALUES
    (@id,       
    @firstname,
    @lastname,
    @middlename,
    @terminationdate)      
    END"

$SQLCmd.Parameters.Add("@id", [System.Data.SqlDbType]::Int).Value = $user.id
$SQLCmd.Parameters.Add("@firstname", [System.Data.SqlDbType]::NVarChar).Value = $user.fname+[DBNull]::Value
$SQLCmd.Parameters.Add("@lastname", [System.Data.SqlDbType]::NVarChar).Value = $user.lastname+[DBNull]::Value
$SQLCmd.Parameters.Add("@middlename", [System.Data.SqlDbType]::NVarChar).Value = $user.middlename+[DBNull]::Value
$SQLCmd.Parameters.Add("@terminationdate", [System.Data.SqlDbType]::Date).Value = $user.terminationdate+[DBNull]::Value

$SQLCmd.ExecuteNonQuery()
于 2019-09-23T14:59:45.740 回答
0

您可以尝试在将 CSV 对象值传递给 SQL 命令之前将其清空。

foreach ($user in $users){

  switch ('id','firstname','lastname','middlename','terminationdate') {
    {[string]::IsNullOrEmpty($user.$_)} {
        Set-Variable $_ -Value $null -Force
        Break
    }
    default {
        Set-Variable $_ -Value $user.$_ -Force
    }
  } # End switch

  # SQL Stuff
} # End foreach loop

这将在循环中创建与属性名称匹配的变量 ( $id, $firstname, $lastname, $middlename, )。$terminationdate然后只需在 switch 块之后添加您的 SQL 代码。

于 2019-09-23T12:28:18.593 回答