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我有一个 angularjs 网页,想要获取指定元素的范围。但是执行reloadWithDebugInfo函数后,结果为null;

    private Page _page;
    private Browser _browser;

    private async void button1_ClickAsync(object sender, EventArgs e)
    {
        try
        {
            await initAsync();
            await test2Async();
        }
        catch (Exception ex)
        {
            MessageBox.Show("Error : " + ex.Message);
        }
    }

    private async Task initAsync()
    {
        _browser = await Puppeteer.LaunchAsync(new LaunchOptions
        {
            Headless = false,
            ExecutablePath = @"c:\Program Files (x86)\Google\Chrome\Application\chrome.exe",
            Timeout = 60000
        });
    }

    private async Task test2Async()
    {
        try
        {
            _page = await _browser.NewPageAsync();

            await _page.GoToAsync("https://SOME Angular JS WebPage");

            await _page.EvaluateFunctionAsync(@"() => angular.reloadWithDebugInfo()");

            var scopeContent = await _page.EvaluateFunctionAsync("() => angular.element(document.getElementsByClassName('left-column-v3')).scope() ");

            // scopeContent is null. why? (the above javascript code runs successfully in the chrome dev console.)
        }
        catch (Exception ex)
        {
            MessageBox.Show("Error : " + ex.Message);
        }
    }

这些语句在 chrome 开发工具中运行良好。我期望范围的 json 内容,但那是空的;

更新:对不起,我在 Scope() 之后忘记了一些东西。我想要一个范围内的变量,而不是范围本身:

        var scopeContent = await _page.EvaluateFunctionAsync("() => angular.element(document.getElementsByClassName('left-column-v3')).scope().SomeVariable ");
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1 回答 1

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问题是作用域函数的结果是不可序列化的。您需要在内部构建一个可序列化的对象EvaluateFunctionAsync并返回它。

Javascript 错误

于 2019-09-10T11:11:21.137 回答