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我的目标是创建一个表单来为包括用户在内的设备添加租金。

device并且 user是用 ForeignKey 实现的,对于user我想要使用django-select2的,因为大量的用户。

模型.py

class Device(models.Model):
    name = models.CharField(
        verbose_name = "Gerätename",
        max_length =       128,
        unique =        True,
        )

    def __str__(self):
        return self.name



class ldap_data(models.Model):
    username = models.CharField(max_length=1024, unique=True)

    class Meta:
        ordering = ('username',)

    def __str__(self):
        return self.username


class Rental(models.Model):
    user = models.ForeignKey(ldap_data, on_delete=models.CASCADE)
    device = models.ForeignKey(Device, on_delete=models.CASCADE)
    date_start = models.DateField()
    date_end = models.DateField()


    class Meta:
        ordering = ('date_start',)

    def __str__(self):
        return self.device

表格.py

class RentalForm(forms.ModelForm):
    user = forms.ChoiceField(
            widget=ModelSelect2Widget(
                model=ldap_data,
                search_fields=['username__icontains']
            )
        )


    date_start = forms.CharField(label="Datum Ausleihe", help_text="", widget=forms.TextInput(attrs={'id': 'datepicker', 'class': 'form-control form-control-sm', 'placeholder': '01.01.2019' }))
    date_end = forms.CharField(label="Datum Rückgabe", help_text="", widget=forms.TextInput(attrs={'id': 'datepicker2', 'class': 'form-control form-control-sm', 'placeholder': '01.01.2019' }))

    class Meta:
        model = Rental
        fields = ['device', 'user', 'date_start', 'date_end',]

该表单到目前为止有效,但如果我从该django-select2字段中选择一个用户user并提交表单,它会抱怨:

Select a valid choice. 1 is not one of the available choices.

看起来表单试图验证所选用户的 pk (=1),而不是usernameof ldap_data。我如何获得用户名 (CharField) 而不是 pk (IntegerField) ?

4

1 回答 1

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我不得不切换到 ModelChoiceField 并设置一个查询集。

class RentalForm(forms.ModelForm):
    user = forms.ModelChoiceField(
            queryset=ldap_data.objects.all(),
            widget=ModelSelect2Widget(
                model=ldap_data,
                search_fields=['username__icontains']
            )
        )
...
于 2019-09-10T20:31:04.103 回答