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我正在使用 Spring 来呈现我的 JSP，我的 url 模式DispatcherServlet是“/”。这似乎使得欢迎文件列表永远不会被考虑。我实际上想DispatcherServlet处理除“/”之外的所有内容。但是，我想避免文件扩展名（例如，*.html、.do 等），并且我使用的是InternalResourceViewResolver.，因此将调度程序 servlet 的 url 模式设置为“/ ”会使其接受太多（例如生成的 JSP 页面的内部请求InternalResourceViewResolver将被调度程序 servlet 拦截，然后会抛出错误，因为它没有 /WEB-INF/jsp/about.jsp 的映射）。任何帮助将不胜感激 - 我对 Spring很陌生（例如 2 天 ;-)）

以下是相应的文件：

目录结构

/war (I'm using AppEngine)
  index.jsp (Simply includes WEB-INF/jsp/index.jsp)
  /WEB-INF
    XML Config files

    /jsp
      index.jsp
      about.jsp
      ...

web.xml

<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">

<welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
</welcome-file-list>

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<!--
    We purposefully do not make this /*. The convention here is to define
    mappings for files that exist, and write a good 404 page for anything
    else. Also, if you say /*, then the dispatcher servlet will intercept
    all requests, and the InternalResourceViewResolver will fail to
    resolve internal resources (e.g. jsp pages) because the dispatcher
    servlet will be intercepting all of the requests, even the internal
    ones
-->
<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

</web-app>

调度程序-servlet.xml

<!-- Search for and import all components in the controllers package -->
<context:component-scan base-package="org.foo.server.controllers" />


<bean name="viewResolver" class="org.springframework.web.servlet.view.XmlViewResolver">
    <property name="order" value="2" />
    <property name="location" value="/WEB-INF/views.xml" />
</bean>

<bean id="multipartResolver"
    class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
    <property name="maxUploadSize" value="100000" />
</bean>


<!--
    Given an arbitrary view name, such as 'about, that has been returned
    from a handler (controller), this will simply create
    '/WEB-INF/jsp/about.jsp' and send that to the Dispatcher Servlet.
    Because of the way ViewResolvers are chained (e.g. search until a View
    is found), coupled with the annoyance that this ViewResolver cannot
    determine if a View is found, this *has* to be the last ViewResolver
    considered, so I have set the order very high. See
    http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/mvc.html#mvc-viewresolver-chaining
    for more details
-->
<bean id="jspResolver"
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="viewClass"
        value="org.springframework.web.servlet.view.JstlView" />
    <property name="prefix" value="/WEB-INF/jsp/" />
    <property name="suffix" value=".jsp" />
    <property name="order" value="999" />
</bean>

JSP 控制器（包含在 org.foo.server.controllers 包中的控制器之一）

@Controller
public class WebportalController {
@RequestMapping(value = "/myforms", method = RequestMethod.GET)
public String getMyForms() {
    return "myforms";
}

@RequestMapping(value = "/about", method = RequestMethod.GET)
public String getAbout() {
    return "about";
}
... etc (for now all of the JSP pages are fairly static)
}
4

1 回答 1

1

我解决这个问题的方法是给 dipatcher servlet 一些前缀，并将带有该前缀的所有内容转发给它（包括扩展）。就我而言，我使用webapp了其他一级目录，例如imagesetc。这是我找到的唯一方法（缺少 URL 重写）来使其工作。此外，如果您愿意，您可以使用 URL 重写引擎webapp从没有扩展名的请求中删除，等等。

于 2011-04-25T13:06:24.997 回答