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我正在使用来自 opencv-python 的 MSER 来使用来自这个stackoverflow question的代码来检测文本。谁能帮我理解为什么在计算对象的凸包之前将轮廓 p 重塑为 (-1, 1, 2) ?

代码如下:

import cv2
import numpy as np

#Create MSER object
mser = cv2.MSER_create()

#Your image path i-e receipt path
img = cv2.imread('/home/rafiullah/PycharmProjects/python-ocr-master/receipts/73.jpg')

#Convert to gray scale
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)

vis = img.copy()

#detect regions in gray scale image
regions, _ = mser.detectRegions(gray)

hulls = [cv2.convexHull(p.reshape(-1, 1, 2)) for p in regions]

cv2.polylines(vis, hulls, 1, (0, 255, 0))

cv2.imshow('img', vis)

cv2.waitKey(0)

mask = np.zeros((img.shape[0], img.shape[1], 1), dtype=np.uint8)

for contour in hulls:

    cv2.drawContours(mask, [contour], -1, (255, 255, 255), -1)

#this is used to find only text regions, remaining are ignored
text_only = cv2.bitwise_and(img, img, mask=mask)

cv2.imshow("text only", text_only)

cv2.waitKey(0)
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1 回答 1

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重塑与否并不重要。

重塑是不必要的。cv2.convexHull()可以采用任何一种输入格式。下图显示,无论是否对contoursinregions进行整形,结果都是相同的。

hulls = [cv2.convexHull(p.reshape(-1, 1, 2)) for p in regions]
hulls1 = [cv2.convexHull(p) for p in regions]

他们是一样的

这是p轮廓在重塑时的变化方式:

>>> p
array([[305, 382],
       [306, 382],
       [308, 380],
       [309, 380]...


>>> p.reshape(-1, 1, 2)
array([[[305, 382]],    
       [[306, 382]],    
       [[308, 380]],    
       [[309, 380]]...
于 2019-08-27T17:01:58.657 回答