HttpClient::sendAsync
仅适用于 Java 11 的解决方案
基于此链接,您可以执行以下操作:
public static void main(String[] args) throws IOException, URISyntaxException, ExecutionException, InterruptedException {
UncheckedObjectMapper uncheckedObjectMapper = new UncheckedObjectMapper();
HttpRequest request = HttpRequest.newBuilder(new URI("https://jsonplaceholder.typicode.com/todos/1"))
.header("Accept", "application/json")
.build();
Model model = HttpClient.newHttpClient()
.sendAsync(request, HttpResponse.BodyHandlers.ofString())
.thenApply(HttpResponse::body)
.thenApply(uncheckedObjectMapper::readValue)
.get();
System.out.println(model);
}
class UncheckedObjectMapper extends com.fasterxml.jackson.databind.ObjectMapper {
/**
* Parses the given JSON string into a Map.
*/
Model readValue(String content) {
try {
return this.readValue(content, new TypeReference<Model>() {
});
} catch (IOException ioe) {
throw new CompletionException(ioe);
}
}
}
class Model {
private String userId;
private String id;
private String title;
private boolean completed;
//getters setters constructors toString
}
我使用了一些提供示例 JSON 输入和示例模型类的虚拟端点来将响应直接映射到Model
使用 Jackson 的类。
Java 11 的解决方案HttpClient::send
和HttpClient::sendAsync
我通过定义 custom 找到了一种方法HttpResponse.BodyHandler
:
public class JsonBodyHandler<W> implements HttpResponse.BodyHandler<W> {
private Class<W> wClass;
public JsonBodyHandler(Class<W> wClass) {
this.wClass = wClass;
}
@Override
public HttpResponse.BodySubscriber<W> apply(HttpResponse.ResponseInfo responseInfo) {
return asJSON(wClass);
}
public static <T> HttpResponse.BodySubscriber<T> asJSON(Class<T> targetType) {
HttpResponse.BodySubscriber<String> upstream = HttpResponse.BodySubscribers.ofString(StandardCharsets.UTF_8);
return HttpResponse.BodySubscribers.mapping(
upstream,
(String body) -> {
try {
ObjectMapper objectMapper = new ObjectMapper();
return objectMapper.readValue(body, targetType);
} catch (IOException e) {
throw new UncheckedIOException(e);
}
});
}
}
然后我称之为:
public static void main(String[] args) throws URISyntaxException, IOException, InterruptedException {
HttpRequest request = HttpRequest.newBuilder(new URI("https://jsonplaceholder.typicode.com/todos/1"))
.header("Accept", "application/json")
.build();
Model model = HttpClient.newHttpClient()
.send(request, new JsonBodyHandler<>(Model.class))
.body();
System.out.println(model);
}
回应是:
Model{userId='1', id='1', title='delectus aut autem', completed=false}
JavaDocHttpResponse.BodySubscribers::mapping
对解决这个问题特别有用。可以进一步改进使用HttpResponse.BodySubscribers::ofInputStream
而HttpResponse.BodySubscribers.ofString(StandardCharsets.UTF_8)
不是BodySubscriber
为JsonBodyHandler
.