我正在尝试将我的 excel 文件上传到MySQL数据库并使用Spout来执行此操作。这是我的 HTML 和 PHP 代码。
<!DOCTYPE html>
<html>
<head>
<title>Excel Uploading PHP</title>
<link rel="stylesheet" type="text/css" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
</head>
<body>
<div class="container">
<h1>Excel Upload</h1>
<form method="POST" action="upload_excel.php" enctype="multipart/form-data">
<div class="form-group">
<label>Upload Excel File</label>
<input type="file" name="file" class="form-control">
</div>
<div class="form-group">
<button type="submit" name="Submit" class="btn btn-success">Upload</button>
</div>
</form>
</div>
</body>
</html>
这是PHP代码
<?php
use Box\Spout\Reader\ReaderFactory;
use Box\Spout\Common\Type;
echo 'File Used';
// Include Spout library
require_once 'Spout/Autoloader/autoload.php';
require 'SpreadsheetReader.php';
echo 'Require complete';
require('db_connection.php');
// check file name is not empty
if (!empty($_FILES['file']['name'])) {
// Get File extension eg. 'xlsx' to check file is excel sheet
$pathinfo = pathinfo($_FILES["file"]["name"]);
print_r($pathinfo);
// check file has extension xlsx, xls and also check
// file is not empty
if (($pathinfo['extension'] == 'xlsx' || $pathinfo['extension'] == 'xls')
&& $_FILES['file']['size'] > 0 ) {
echo 'File validated';
$inputFileName = 'uploads/'.$_FILES['file']['name'];
move_uploaded_file($_FILES['file']['tmp_name'], $inputFileName);
$Reader = new SpreadsheetReader($inputFileName);
echo $inputFileName;
try
{
$reader = ReaderFactory::create(Type::XLSX);
echo 'Reader successful';
}
catch(Exception $e)
{
echo $e->getMessage();
}
// Read excel file by using ReadFactory object.
echo 'opening file';
// Open file
$reader->open($inputFileName);
$count = 1;
// Number of sheet in excel file
foreach ($reader->getSheetIterator() as $sheet) {
// Number of Rows in Excel sheet
foreach ($sheet->getRowIterator() as $row) {
// It reads data after header. In the my excel sheet,
// header is in the first row.
if ($count > 1) {
// Data of excel sheet
$data['<column_name>'] = $row[0];
$data['<column_name>'] = $row[1];
$data['<column_name>'] = $row[2];
$data['<column_name>'] = $row[3];
$data['<column_name>'] = $row[3];
$data['<column_name>'] = $row[3];
$data['<column_name>'] = $row[3];
$data['<column_name>'] = $row[3];
$data['<column_name>'] = $row[3];
$data['<column_name>'] = $row[3];
$query = "<SQL QUERY GOES HERE>";
$result = mysqli_query($conn, $query);
print_r(data);
}
$count++;
}
}
// Close excel file
$reader->close();
} else {
echo "Please Select Valid Excel File";
}
} else {
echo "Please Select Excel File";
}
?>
我写了一些 PHP echo' 来检查程序的流程。该文件完美运行，直到以下行：move_uploaded_file($_FILES['file']['tmp_name'], $inputFileName);然后停止执行。
它复制给定文件夹中的文件并在尝试创建SpreadsheetReader对象时停止。我试图Try-Catch在它周围放置块以捕获任何异常错误，但也没有捕获任何异常。
让我给你设置的状态：
以上所有内容都托管VPS并运行在Ubuntu 18.10. spout 不是使用 composer 安装的，我已经从预安装的源中复制了文件。
我是否缺少任何必须在操作系统上安装才能解决此问题的软件包？还是程序本身缺少什么？我搜索了参考资料，但根据文章，这段代码似乎有效。我很困惑，问题出在哪里？
请有人给我指导以寻找或至少给我一个关于工作 Excel-MySQL 文件上传的参考。
谢谢