4

大家好,
我有一个将一些数据发布到服务器的 AsyncTask。它通过调用我从 doInBackground 编写的静态方法来实现这一点。当我运行 AsyncTask 时,我发送调用 execute() 的活动的上下文,我将其发送到我的静态方法,因为如果在与服务器通信时出现问题,它需要它来制作 Toast。但是,当在静态方法中创建 Toast 时出现此错误:

04-21 12:49:16.689: ERROR/AndroidRuntime(2123): FATAL EXCEPTION: AsyncTask #1
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): java.lang.RuntimeException: An error occured   while executing doInBackground()
04-21 12:49:16.689: ERROR/AndroidRuntime(2123):at android.os.AsyncTask$3.done(AsyncTask.java:200)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:274)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.util.concurrent.FutureTask.setException(FutureTask.java:125)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:308)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.util.concurrent.FutureTask.run(FutureTask.java:138)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1088)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:581)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.lang.Thread.run(Thread.java:1019)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at android.os.Handler.<init>(Handler.java:121)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at android.widget.Toast.<init>(Toast.java:68)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at android.widget.Toast.makeText(Toast.java:23
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at com.microogle.dev.util.ServerConnections.PostToLoginPage(ServerConnections.java:36)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at com.microogle.dev.Whiteboard.WhiteboardLogin$LoginTask.doInBackground(WhiteboardLogin.java:150)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at com.microogle.dev.Whiteboard.WhiteboardLogin$LoginTask.doInBackground(WhiteboardLogin.java:1)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at android.os.AsyncTask$2.call(AsyncTask.java:185)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:306)
04-21 12:49:16.689: ERROR/AndroidRuntime(2123): ... 4 more

随后是泄漏的窗口错误。我假设这是因为在静态方法中传递给 Toast 的上下文出错。AsyncTask 是:

private class LoginTask extends AsyncTask<Void, Void, Void> {

    private WhiteboardLogin activity;
    private Context callingContext;
    private ProgressDialog dialog;
    private String user, pass;
    private boolean sendIntent = true, loginError = false, populateError = false;

    public LoginTask(WhiteboardLogin activity, String user, String pass, Context callingContext){
        this.activity = activity;
        this.user = user.trim();
        this.pass = pass.trim();
        this.callingContext = callingContext;
    }
@Override
    protected Void doInBackground(Void... params) {
        ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
        nameValuePairs.add(new BasicNameValuePair("user",user));
        nameValuePairs.add(new BasicNameValuePair("pass",pass));
        sessionUser = user;
        sessionPassword = pass;
        //Posts the username and password to the login page and toasts an error if the login doesn't work 
        if(ServerConnections.PostToLoginPage(callingContext, nameValuePairs, activity.getString(R.string.loginPageURI)) == 1){
            dialog.dismiss();
            sendIntent = false;
            loginError = true;
            publishProgress();
           return null;
        }
        else{
           userDataList = populateUserDataList(callingContext, user,pass);
           if(userDataList == null){
               dialog.dismiss();
               sendIntent = false;
               populateError = true;
               return null;
           }
       }
       return null;
    }
4

4 回答 4

22

doInBackground() 方法中的代码在其自己的线程上运行,因此您无法直接从那里访问任何 UI 元素,因为它们在 UI 线程上运行。

所以你有两个选择。

  1. 您处理在 UI 线程上运行的onPreExecute()onPostExecute()方法中的所有 UI 内容。

  2. 您在onProgressUpdate()方法中处理 UI 内容,该方法也运行在 UI 线程上。您可以通过调用publishProgress()从 doInBackground() 中触发此方法。

于 2011-04-21T17:35:00.163 回答
2

你可以在 doInBackground 里面 Toast

使用此代码

runOnUiThread(new Runnable() {
public void run() {

    Toast.makeText(<your class name>.this, "Cool Ha?", Toast.LENGTH_SHORT).show();
    }
});
于 2013-04-07T18:29:45.877 回答
1

您正在尝试更新在doInBackground()不同于 UI 线程的另一个线程中运行的 UI。onPostExecute()您应该在 AsyncTask的方法中显示 Toast :http: //developer.android.com/reference/android/os/AsyncTask.html#onPostExecute (Result )

于 2011-04-21T17:37:31.967 回答
0

是的,使用日志进行调试是最简单的,但是如果您确实有消息需要在后台处理期间出于某种原因显示,您可以使用 onProgressUpdate() 方法,如 Flo 上面所述。您可以在需要编写消息时触发此方法,方法是从 DoInBackground() 中调用 publishProgress()。消息内容或处理状态可以通过 ASyncTask 中的私有变量轻松传递,Background 方法和 UI 方法都可以访问这些私有变量。

于 2011-06-20T17:41:27.497 回答