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我想在函数中使用函数，但我得到错误我想获取上一个对象、当前对象和下一个对象我如何定义任何人都可以帮助我？实际上我是编程新手提前谢谢你

class DataHandler:
    def previous_and_next(some_iterable):
        prevs, items, nexts = tee(some_iterable, 3)
        prevs = chain([None], prevs)
        nexts = chain(islice(nexts, 1, None), [None])
        return zip(prevs, items, nexts)



    def current_obj(self):
        print("The current object is : ",employee_list[0])

    def next_obj(se):
        property = previous_and_next(employee_list)
        for previous, item, nxt in property:
            print("Item is now", item, "next is", nxt, "previous is", previous)

employee_list = []
n = int(input("Enter number of Employee you want to add:"))
for i in range(n):
    fname = input("Enter First name : ")
    lname = input("Enter Last name : ")
    emp_type = input("Enter Employee type : ")
    details = [fname,lname,emp_type]
    print(details)
    employee_list.append(details)


obj = DataHandler()
obj.current_obj()
obj.next_obj()

我收到错误：property = previous_and_next(employee_list) NameError: name 'previous_and_next' is not defined

4

2 回答 2

2

您的问题是您正在尝试访问属于类实例的方法。您需要使用self：

def next_obj(self):
    property = self.previous_and_next(employee_list)
    for previous, item, nxt in property:
        print("Item is now", item, "next is", nxt, "previous is", previous)

您还需要使该previous_and_next方法self作为参数，或使其成为staticmethod：

def previous_and_next(self, some_iterable):

或者

@staticmethod
def previous_and_next(some_iterable):

我不相信您的其余代码实际上会达到预期的结果，但这应该可以解决您遇到的错误。

于 2019-08-06T09:10:17.310 回答
1

那么你可以通过定义函数self。只需在所有功能中添加 self ，然后您就可以使用：

def previous_and_next(self,some_iterable):
        prevs, items, nexts = tee(some_iterable, 3)
        prevs = chain([None], prevs)
        nexts = chain(islice(nexts, 1, None), [None])
        return zip(prevs, items, nexts)

属性 = self.previous_and_next(employee_list)

于 2019-08-06T09:14:38.817 回答