如何使用 SwiftUI 在 Xcode 11 中设置 SF 符号的大小?
问问题
33805 次
4 回答
130
SF 符号类似于字体,因此:
.font(.system(size: 60))
于 2019-08-03T21:20:31.867 回答
61
您可以设置重量和尺寸:
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .ultraLight))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .thin))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .light))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .regular))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .medium))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .semibold))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .bold))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .heavy))
Image(systemName: "checkmark.circle")
.font(.system(size: 16, weight: .black))
于 2019-11-15T04:00:26.650 回答
53
另一种方法是使用.imageScale()
.
Image(systemName: "chevron.left").imageScale(.small)
Image(systemName: "chevron.left").imageScale(.medium)
Image(systemName: "chevron.left").imageScale(.large)
于 2020-06-04T15:09:09.913 回答
2
如果你想使用框架,你也可以:
Image(systemName: "plus")
.resizable()
.scaledToFit()
.frame(width: 24, height: 24)
于 2022-02-23T13:46:24.067 回答