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你们能帮我知道如何在我的 PySimpleGui 脚本中连接一个按钮，当按下/单击运行按钮时，它将执行另一个 python 脚本。

现在，我一直在阅读关于 GUI 脚本中的 Subprocess 和 command = os.popen 的内容。

layout = [[ sg.Text('Click the button to launch Program')],
           [sg.Button('Launch')]]

win1 = sg.Window('My new window').Layout(layout)


win2_activate = False

while True:
    ev1, vals1 = win1.Read()
    if ev1 is None or ev1 == 'Cancel':
        break

    if not win2_activate and ev1 == 'Launch':
        win1.Hide()
        win2_activate = True
        layout2 = [[sg.Text('Report Auto')],
                    [sg.Input(do_not_clear=True)],
                    [sg.Text('', key='_OUTPUT_')],
                    [sg.Button('Run'), sg.Button('Cancel')]]

        win2 = sg.Window('Window2').Layout(layout2)
        while True:        
            ev2, vals2 = win2.Read()
            if ev2 is None or ev2 =='Cancel':
                win2_activate = False
                win2.Close()
                win1.UnHide()
                break

在我的 pysimplegui 脚本中，我还没有包含子进程或任何库，因为我只是不知道在哪里做。任何帮助将是最受欢迎的！

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2 回答 2

1

这是您问题的完整答案，一个 PySimpleGUI 程序。该程序允许您输入命令。然后按一个按钮。按下按钮时，命令为“运行”，输出显示在窗口中。

import subprocess
import sys
import PySimpleGUI as sg

def main():
    layout = [  [sg.Text('Enter a command to execute (e.g. dir or ls)')],
                [sg.Input(key='_IN_')],             # input field where you'll type command
                [sg.Output(size=(60,15))],          # an output area where all print output will go
                [sg.Button('Run'), sg.Button('Exit')] ]     # a couple of buttons

    window = sg.Window('Realtime Shell Command Output', layout)

    while True:             # Event Loop
        event, values = window.Read()
        if event in (None, 'Exit'):         # checks if user wants to exit
            break

        if event == 'Run':                  # the two lines of code needed to get button and run command
            runCommand(cmd=values['_IN_'], window=window)

    window.Close()

# This function does the actual "running" of the command.  Also watches for any output. If found output is printed
def runCommand(cmd, timeout=None, window=None):
    p = subprocess.Popen(cmd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    output = ''
    for line in p.stdout:
        line = line.decode(errors='replace' if (sys.version_info) < (3, 5) else 'backslashreplace').rstrip()
        output += line
        print(line)
        window.Refresh() if window else None        # yes, a 1-line if, so shoot me
    retval = p.wait(timeout)
    return (retval, output)                         # also return the output just for fun

if __name__ == '__main__':
    main()
于 2019-07-26T23:45:28.110 回答
0

要让按钮执行某项操作，您只需键入：

if event in #<enter KEY here>:
    #do your action

将 KEY 替换为按钮的键（通常是名称，在您的情况下为“启动”）

然后使变量（例如LaunchWindow）为真，而不是从另一个窗口调用“启动”按钮。我不认为 PySimpleGUI 喜欢那样...

于 2020-03-03T07:56:50.843 回答