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我的主目录中有一个 csv 文件,如下所示

cat try.csv
val1,val2,val3,val4,val5,val6
10-Jul-19,12604876601113439,Self,abs,Tier-I,30088.5
09-Jul-19,12604876601112397,Self,abs,Tier-I,200590
08-Jul-19,12604876601111807,Self,abs,Tier-I,200590
05-Jul-19,12604876601109069,Self,abs,Tier-I,70206.5
29-May-19,12604876601085648,Self,cdf,Tier-I,70206.5
30-Apr-19,12604876601068094,Self,cdf,Tier-I,130383.5
15-Nov-18,12604876600900949,Self,xyz,Tier-I,71209.46
10-Oct-18,12604876600887501,Self,xyz,Tier-I,79233.06

我可以使用grep命令来提取包含单词'abs'的行:

grep -w 'abs' try.csv
10-Jul-19,12604876601113439,Self,abs,Tier-I,30088.5
09-Jul-19,12604876601112397,Self,abs,Tier-I,200590
08-Jul-19,12604876601111807,Self,abs,Tier-I,200590
05-Jul-19,12604876601109069,Self,abs,Tier-I,70206.5

ripgrep但是我在https://blog.burntsushi.net/ripgrep/中遇到过它声称具有类似的功能grep但执行速度更快(我的实际 csv 文件非常大,大小为 30gb,所以我需要一些比 更快的方法grep

所以我安装ripgrepcargo install ripgrep运行以下代码

ripgrep -w 'abs' try.csv

但我得到以下错误

Command 'ripgrep' not found, did you mean:

  command 'sipgrep' from deb sipgrep
  command 'zipgrep' from deb unzip

Try: apt install <deb name>

任何以正确方式使用 ripgrep 的指针都会有所帮助

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1 回答 1

1

该程序被调用ripgrep,但它被调用rg。您需要做的就是:

rg -w 'abs' try.csv
于 2019-07-21T21:55:49.727 回答