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我正在使用 Spring Data - 多列搜索和Spring Data Jpa - 类型 Specifications<T>在我想搜索多个列（如Date（Java 8 LocalDateTime、Instant等LocalDate）Integer和String数据类型时已弃用）。

但根据我的代码，只有String字段被考虑（根据登录where子句）::

select
    employee0_.employee_id as employee1_0_,
    employee0_.birth_date as birth_da2_0_,
    employee0_.email_id as email_id3_0_,
    employee0_.first_name as first_na4_0_,
    employee0_.last_name as last_nam5_0_,
    employee0_.project_association as project_6_0_,
    employee0_.status as status7_0_ 
from
    employee employee0_ 
where
    employee0_.first_name like ? 
    or employee0_.email_id like ? 
    or employee0_.status like ? 
    or employee0_.last_name like ?

下面是我开发的代码。

雇员.java

@Builder
@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
public class Employee implements Serializable{
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name="EMPLOYEE_ID")
    private Long employeeId;

    @Column(name="FIRST_NAME")
    private String firstName;

    @Column(name="LAST_NAME")
    private String lastName;

    @Column(name="EMAIL_ID")
    private String email;

    @Column(name="STATUS")
    private String status;

    @Column(name="BIRTH_DATE")
    private LocalDate birthDate;

    @Column(name="PROJECT_ASSOCIATION")
    private Integer projectAssociation;
}

注意：用户可以使用全局搜索搜索任何值，无论用户搜索什么，都应该能够看到数据，而不管数据类型如何。

EmployeeSpecification.java

public class EmployeeSpecification {

    public static Specification<Employee> textInAllColumns(String text, List<String> attributes) {
        if (!text.contains("%")) {
            text = "%" + text + "%";
        }
        final String finalText = text;

        return (root, query, builder) -> builder
                .or(root.getModel().getDeclaredSingularAttributes().stream().filter(a -> {
                    if (a.getJavaType().getSimpleName().equalsIgnoreCase("String")) {
                        return true;
                    }else if(a.getJavaType().getSimpleName().equalsIgnoreCase("date")) {
                        return true;
                    }
                    else {
                        return false;
                    }
                }).map(a -> builder.like(root.get(a.getName()), finalText)).toArray(Predicate[]::new));
    }
}

但是这种方法只考虑字符串字段而不考虑日期和整数数据类型。我们怎样才能做到这一点？

4

2 回答 2

0

改变：

if(a.getJavaType().getSimpleName().equalsIgnoreCase("date"))

到：

if(a.getJavaType().getSimpleName().equalsIgnoreCase("LocalDate"))
于 2019-07-21T15:41:41.927 回答
0

分析问题，我给你一个更灵活的解决方案，这段代码解决了你的问题，并允许动态生成动态查询。这个想法是使用任何类型的对象来进行查询。

首先，创建这个类来保存查询的参数

@RequiredArgsConstructor
public class Search {
    @Getter
    @NonNull private String field;
    @Getter
    @NonNull private String operator;
    @Getter
    @NonNull private Object value;
}

然后根据以下代码为每个对象构建规范

public static Specification<Employee> searchFreeAttrsEmployee(List<Search> attributes) {
    return new Specification<Employee>() {
        private static final long serialVersionUID = 4817323527595445596L;
        public Predicate toPredicate(Root<Employee> root, CriteriaQuery<?> query, CriteriaBuilder builder) {
            List<Predicate> r=new ArrayList<Predicate>(); 
            attributes.stream().forEach(t -> {
                r.add(setParams(t, root, builder));
            });
            Predicate list[] = new Predicate[r.size()];
            r.toArray(list);
            return builder.or(list);
        }
    };
}

public static Predicate setParams(Search t, Root<?> root, CriteriaBuilder builder) {
    if (t.getOperator().equals("like")) {
        return builder.like(root.get(t.getField()), t.getValue().toString());
    }
    if (t.getOperator().equals("equal")) {
        return builder.equal(root.get(t.getField()), t.getValue().toString());
    }       
    if (t.getOperator().equals("gtInt")) {
        return builder.gt(root.get(t.getField()), Integer.valueOf(t.getValue().toString()));
    }       
    if (t.getOperator().equals("eqInt")) {
        return builder.equal(root.get(t.getField()), Integer.valueOf(t.getValue().toString()));
    }       

    return null;
}

}

以这种方式运行搜索

    List<Search> l=new ArrayList<Search>();
    l.add(new Search("firstName","like","Peter"));
    List<Employee> list = pe.findAll(Specifications.searchFreeAttrsEmployee(l));

您可以聚合许多属性来进行搜索。我希望这段代码会有用。

问候

于 2019-07-23T16:14:03.510 回答