jpa-2.0 - 如何动态创建 CriteriaQuery

Question

我想为此查询创建等效的 CriteriaQuery ： select u from User u where u.name = "John" and u.surname = "Black" and u.middlename = "Small"; 但我对“where”谓词有疑问。谢谢

Answer 1

您可以使用：

CriteriaBuilder builder = entityManager.getCriteriaBuilder();
CriteriaQuery c = ...;
Root root = ...;

Predications name = builder.equal(root.get("name"), name);
Predications surname = ...;
Predications middlename = ...;

c.where(name, surname, middlename);