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我有一个具有 EmbeddedModelField (embedmodel) 的模型 (parentmodel)。这基本上是 MongoDB 中的文档。下面是模型类

class embedmodel(models.Model):
    sendto = models.CharField(max_length=10)
    sendtouser = models.CharField(max_length=15)
    sendtogroup = models.CharField(max_length=15)

    class parentmodel(models.Model):
    name = models.CharField(max_length=30, unique=True, primary_key=True)
    type = models.CharField(max_length=11)
    enabled = models.BooleanField()
    rule = models.EmbeddedModelField(model_container=embedmodel)

    class Meta:
        managed = False
        db_table = 'parentmodel'

这就是我在 mongodb 中的文档的样子

{
    'name': 'rule1',
    'type': 'static',
    'enabled': True,
    'rule': {
        'sendto': 'external',
        'sendtouser': 'sam',
        'sendtogroup': 'vendor'
    }
}

我正在尝试创建一个表单来帮助我创建新规则，这就是我在 forms.py 中的内容，我也想自定义表单字段。

class RulesForm(forms.ModelForm):
    name = forms.CharField(max_length=30, required=True)
    type = forms.CharField(max_length=11, required=True)
    enabled = forms.BooleanField(widget=forms.CheckboxInput)

    class Meta:
        model = parentmodel
        fields = ['name', 'type', 'enabled', 'rule']

如何自定义从 embedmodel 中显示的字段？我尝试了以下但没有运气。

class RulesForm(forms.ModelForm):
    name = forms.CharField(max_length=30, required=True)
    type = forms.CharField(max_length=11, empty_value="UserDefined", required=True
    enabled = forms.BooleanField(widget=forms.CheckboxInput)
    sendto = forms.ChoiceField(widget=forms.Select, choices=[(1, 'External'), (2, 'Internal')])
    sendtouser = forms.CharField(max_length=30, required=False)
    sendtogroup = forms.CharField(max_length=30, required=False)
    class Meta:
        model = Rules
        fields = ['name', 'type', 'enabled', 'rule']

和

class RulesForm(forms.ModelForm):
    name = forms.CharField(max_length=30, required=True)
    type = forms.CharField(max_length=11, empty_value="UserDefined", required=True
    enabled = forms.BooleanField(widget=forms.CheckboxInput)
    embedmodel.sendto = forms.ChoiceField(widget=forms.Select, choices=[(1, 'External'), (2, 'Internal')])
    embedmodel.sendtouser = forms.CharField(max_length=30, required=False)
    embedmodel.sendtogroup = forms.CharField(max_length=30, required=False)
    class Meta:
        model = Rules
        fields = ['name', 'type', 'enabled', 'rule']
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1 回答 1

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我能够通过遵循https://medium.com/@SiddyZen/create-embedded-models-using-django-admin-3ecc38a00879来解决这个问题（在标题为“嵌入式模型”的部分中）感谢作者 SiddyZen :) . 在 models.py 中是否发生了以下变化

from django import forms

class embedmodel(models.Model):
sendto = models.CharField(max_length=10)
sendtouser = models.CharField(max_length=15)
sendtogroup = models.CharField(max_length=15)

class embedmodelForm(forms.ModelForm):
    sendto = forms.ChoiceField(widget=forms.Select, choices=[(1, 'External'), (2, 'Internal')])
    sendtouser = forms.CharField(max_length=15, required=False)
    sendtogroup = forms.CharField(max_length=15, required=False)
    class Meta:
        model = embedmodel
        fields = ['sendto', 'sendtouser', 'sendtogroup']

class parentmodel(models.Model):
name = models.CharField(max_length=30, unique=True, primary_key=True)
type = models.CharField(max_length=11)
enabled = models.BooleanField()
rule = models.EmbeddedModelField(model_container=embedmodel, model_form_class=embedmodelForm)
    class Meta:
    managed = False
    db_table = 'parentmodel'
于 2019-07-19T10:12:21.443 回答