我有两个 emf 模型 A 和 B,其中 B 仅与 A 不同,因为它有一个额外的子节点。
现在我想使用代码中的 emf compare 来做:
1)读取模型A和B并创建模型C,它是A和B的合并模型。基本上这对应于A +来自B的额外节点。
我看过:
但是我看不到如何使用代码计算最终的合并模型:
DiffModel diff = CompareUtils.compare(model1, model2, Collections.<String, Object> emptyMap());
CompareUtils.merge(diff);
任何显示如何计算合并模型的示例?
我现在尝试过:
private void bob() {
ResourceSet resourceSet = new ResourceSetImpl();
Map extensionMap = (Map) resourceSet.getResourceFactoryRegistry()
.getExtensionToFactoryMap().put("xmi", new XMIResourceFactoryImpl());
try {
Region region01 = StatemachineFactoryImpl.eINSTANCE.createRegion();
addResourceToModel(resourceSet, region01, "st1.xmi");
State state01 = StatemachineFactoryImpl.eINSTANCE.createState();
state01.setName("aaaa");
region01.getState().add(state01);
if (state01.eResource() == null) {
System.out.println("state01 NOT contained in resource!");
return;
}
Region region02 = StatemachineFactoryImpl.eINSTANCE.createRegion();
addResourceToModel(resourceSet, region02, "st2.xmi");
State state02 = StatemachineFactoryImpl.eINSTANCE.createState();
state02.setName("bbbb");
region02.getState().add(state02);
if (state02.eResource() == null) {
System.out.println("state02 NOT contained in resource!");
return;
}
final MatchModel match = MatchService.doMatch(region01, region02,
Collections.<String, Object> emptyMap());
final DiffModel diff = DiffService.doDiff(match, false);
final List<DiffElement> differences = new ArrayList<DiffElement>(
diff.getOwnedElements());
MergeService.merge(differences, true);
// Prints the results
addResourceToModel(resourceSet, match, "match.xmi");
addResourceToModel(resourceSet, diff, "diff.xmi");
if (match.eResource() != null)
System.out.println(ModelUtils.serialize(match)); // Throws an
// exception!
if (diff.eResource() != null)
System.out.println(ModelUtils.serialize(diff));
} catch (final InterruptedException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
private void addResourceToModel(ResourceSet resourceSet, EObject obj,
String path) {
Resource res = resourceSet.createResource(URI.createURI(path));
res.getContents().add(obj);
}
但是这条线:
if (match.eResource() != null)
System.out.println(ModelUtils.serialize(match)); // Throws an
// exception!
即使 match.eResource() != null
我收到此错误:
org.eclipse.emf.ecore.resource.Resource$IOWrappedException: The object 'statemachine.impl.StateImpl@11ce012 (name: bbbb)' is not contained in a resource.
at org.eclipse.emf.ecore.xmi.impl.XMLSaveImpl.endSave(XMLSaveImpl.java:306)
at org.eclipse.emf.ecore.xmi.impl.XMLSaveImpl.save(XMLSaveImpl.java:235)
at org.eclipse.emf.ecore.xmi.impl.XMLResourceImpl.doSave(XMLResourceImpl.java:254)
at org.eclipse.emf.ecore.xmi.impl.XMLResourceImpl.save(XMLResourceImpl.java:229)
at org.eclipse.emf.compare.util.ModelUtils.serialize(ModelUtils.java:429)
我已根据此处的文档将 Region 添加到资源中:
并且该州包含在该地区中,所以我不明白为什么我会得到例外……有什么想法吗?