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我正在尝试编写我的第一个 PHP 脚本，但我很挣扎，主要问题是连接/执行部分不起作用，而是抛出“无法连接到服务器”消息......

尝试更改代码 if 语句。

<?php
  include('Net/SSH2.php');
  //Coded by Aaron Akhtar
  //May not be the best code, this is my first ever php script ;P

  //edit the information below to match your ssh details or this will not work!
  $address = "104.xxx.xx.xx";
  $user = "root"; //do not change unless you are using another user from root
  $password = "xxxxx";

  $command = $_GET["command"];

  if(empty($command)){
    echo "Please specify a command to send to the server...";
    die();
  }

    function execute(){
    $connection = ssh2_connect($address, 22);
    if(ssh2_auth_password($connection, $user, $password)){
      echo ssh2_exec($connection, $command);
    }else {
      die("Could not connect to server...");
    }

  }

  execute();

 ?>

我试图让它向我的远程服务器发送命令。

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1 回答 1

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尝试以下更改：

function execute($address,$user, $password, $command){
    $connection = ssh2_connect($address, 22);
    if(ssh2_auth_password($connection, $user, $password)){
        echo ssh2_exec($connection, $command);
    }else {
        die("Could not connect to server...");
    }
}

execute($address,$user, $password, $command);

您在函数内部引用的变量实际上并不可用，它们需要在调用函数时作为参数传入，就像我在上面的代码片段中所做的那样，或者通过在函数内部全局声明它们。

于 2019-07-10T10:47:27.887 回答