4

正如标题所说..如何将图像移动/重命名到新文件夹?到目前为止我有这个,新图像被调整大小/裁剪,但它没有移动到“新/”文件夹:

$in_filename = '4csrWqu9ngv.jpg';

list($width, $height) = getimagesize($in_filename);

$offset_x = 0;
$offset_y = 0;

$new_height = $height - 65;
$new_width  = $width;

$image     = imagecreatefromjpeg($in_filename);
$new_image = imagecreatetruecolor($new_width, $new_height);
imagecopy($new_image, $image, 0, 0, $offset_x, $offset_y, $width, $height);

header('Content-Type: image/jpeg');
imagejpeg($new_image);

$move_new = imagejpeg($new_image);

rename($move_new, 'new/' . $move_new);

一如既往地感谢任何帮助:)

4

2 回答 2

5

您的代码中几乎没有错误。的输出imagejpeg是一个布尔值,所以你的重命名总是失败。您也从未保存调整大小的图像。您必须使用第二个参数imagejpeg并提供新图像的正确文件名。另外,请确保目录new存在,否则重命名将失败。

固定代码:

$in_filename = '4csrWqu9ngv.jpg';

list($width, $height) = getimagesize($in_filename);

$offset_x = 0;
$offset_y = 0;

$new_height = $height - 65;
$new_width  = $width;

$image = imagecreatefromjpeg($in_filename);
$new_image = imagecreatetruecolor($new_width, $new_height);
imagecopy($new_image, $image, 0, 0, $offset_x, $offset_y, $width, $height);

/* Uncomment in case you want it also outputted
header('Content-Type: image/jpeg');
imagejpeg($new_image);
*/

imagejpeg($new_image, $in_filename);

rename($in_filename, 'new/' . $in_filename);
于 2011-04-17T10:25:40.837 回答
0

“新”文件夹是否存在?如果没有,您需要首先使用mkdir.

于 2011-04-17T08:43:17.143 回答