1

我一直在尝试创建一个服务器控件。我一直在尝试让我的 MenuItem 像这样在它下面包含其他 MenuItems

<cc1:DynamicMenu ID="DynamicMenu1" runat="server">
    <MenuItems>
        <cc1:MenuItem Text="" Url="">
            <cc1:MenuItem Text="" Url="">
                <cc1:MenuItem Text="" Url=""></cc1:MenuItem>
            </cc1:MenuItem>
            <cc1:MenuItem Text="" Url="">
                <cc1:MenuItem Text="" Url=""></cc1:MenuItem>
            </cc1:MenuItem>                
        </cc1:MenuItem>
    </MenuItems>
</cc1:DynamicMenu>

但我的代码只给了我这个

<cc1:DynamicMenu ID="DynamicMenu1" runat="server">
    <MenuItems>
        <cc1:MenuItem Text="" Url="">No other child elements for MenuItem</cc1:MenuItem>
    </MenuItems>
</cc1:DynamicMenu>

我玩过 ParseChildren 和 PersistChildren 从真或假交换那里的值，我已经没有想法可以请有人帮我解决我的问题下面是我的代码。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.ComponentModel;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Security.Permissions;
using System.Collections;

namespace Gravity.Controls
{
[AspNetHostingPermission(SecurityAction.Demand, Level = AspNetHostingPermissionLevel.Minimal)]
[AspNetHostingPermission(SecurityAction.InheritanceDemand, Level = AspNetHostingPermissionLevel.Minimal)]
[ParseChildren(true), PersistChildren(true)]
[ToolboxData("<{0}:DynamicMenu runat=\"server\"></{0}:DynamicMenu>")]    
public class DynamicMenu : WebControl
{
    public DynamicMenu()
    {

    }

    List<MenuItem> _menuItems;
    [PersistenceMode(PersistenceMode.InnerProperty)]          
    public List<MenuItem> MenuItems
    {
        get
        {
            if(_menuItems == null)
                _menuItems = new List<MenuItem>();
            return _menuItems;
        }
    }
}

[ParseChildren(false), PersistChildren(true)]    
public class MenuItem: INamingContainer
{
    private string _text;
    private string _url;

    public MenuItem(string text, string url)
    {

    }
    public MenuItem()
        : this("", "")
    {

    }

    public string Text
    {
        get
        {
            return _text;
        }
        set
        {
            _text = value;
        }
    }

    public string Url
    {
        get
        {
            return _url;
        }
        set
        {
            _url = value;
        }
    }

    private List<MenuItem> _subMenuItems;       
    public List<MenuItem> SubMenuItems
    {
        get
        {
            if (_subMenuItems == null)
                _subMenuItems = new List<MenuItem>();
            return _subMenuItems;
        }
    }
}
}
4

2 回答 2

1

您需要在 OnItemDataBound 事件中将自定义控件的实例动态添加到自身。这将在 OnItemDataBound 中满足您的业务逻辑条件（即：没有子项，所以不要添加另一个控件）之前重复。

于 2011-04-17T03:29:12.483 回答
1

我认为你应该使用这些属性：

[ParseChildren(true), PersistChildren(false)]  
public class DynamicMenu

和

[ParseChildren(typeof(MenuItem), DefaultProperty = "SubMenuItems", ChildrenAsProperties = true)] 
public class MenuItem
于 2011-08-14T09:59:45.573 回答