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我讨厌一直问基本问题，看起来像个十足的白痴，但在我能坐下来掌握 Javascript 和 jQuery 之前，我必须依靠你们这里善良和慷慨的人。

我正在调用标记为“_featured”的 Tumblr 帖子，如果它是包含图像的文本帖子，则将它们与图像一起显示在侧边栏中。唯一的问题是图像本身没有链接。没什么大不了的，但有点不直观。我将如何解决这个问题？

和代码：

/*
    TUMBLR FEATURED POSTS SCRIPT
    Automatically gets all posts tagged with "featured" and lists them
    REQUIRES JQUERY!
    --------------------------------------
    Created by james <at> bandit.co.nz
    http://blog.bandit.co.nz

    Some code borrowed from Jacob DeHart's AJAX Search:
    http://blog.bandit.co.nz/post/80415548/tumblr-ajax-inline-search
*/
Featured = {
    'apiNum' : 50, // how many posts to read
    'listId' : '_featured', // the id of the ul to write to
    'tagName' : '_featured', // the name of the tag we're searching for
    'linkAppend' : '', // html to append to the end of each linked post

    'postDB' : [],
    'listPos' : 0,
    'doList' : function (where) {
        var li; var ul = $('#'+where);
        var titles = {"link":"link-text", "photo":"photo-caption", "quote":"quote-text", "regular":"regular-title", "video":"video-caption"}

        // cycle through post database
        pcount = Featured.postDB.length;
        for(i=Featured.listPos;i<pcount;i++) {
            p = Featured.postDB[i];
            if(p[titles[p.type]] != '') titlestr = p[titles[p.type]].replace(/<\/?[^>]+>/gi, '');
            else titlestr = p['url'];

            li = document.createElement('li');
            $(li).append($(p['regular-body']).find('img')[0])
            .append('<div class="featurelink"><a class="'+p.type+'" href="'+p["url-with-slug"]+'">'+titlestr+Featured.linkAppend+'</a></div>');
            ul.append(li);

            Featured.listPos = pcount;
        }
    },

    'getData' : function() {
        $.get('/api/read/json?num='+Featured.apiNum+'&tagged='+Featured.tagName,
            function(data) {
                eval(data);
                for(i=0;i<tumblr_api_read.posts.length;i++) {
                    Featured.postDB.push(tumblr_api_read.posts[i]);
                    Featured.doList(Featured.listId);
                }
            }
        );
    }
};

$(document).ready(function(){
    Featured.getData();
});

与往常一样，任何帮助都会得到我无尽的感激。

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1 回答 1

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您的问题是您将图像附加到<li>当您想要它在里面时<a>，它将在里面<li>。从此更改您的列表项构建器：

li = document.createElement('li');
$(li).append($(p['regular-body']).find('img')[0])
     .append('<div class="featurelink"><a class="'+p.type+'" href="'+p["url-with-slug"]+'">'+titlestr+Featured.linkAppend+'</a></div>');
ul.append(li);

像这样：

$li = $('<li>');
$li.append('<div class="featurelink"><a class="' + p.type + '" href="' + p["url-with-slug"] + '">' + titlestr + Featured.linkAppend + '</a></div>');
$li.find('a').prepend($(p['regular-body']).find('img')[0]); // The important part
ul.append($li);

应该做的伎俩。更改构建<a>内部<li>，然后将图像放在<a>. 您可能需要稍微调整 CSS 以获得所需的布局，可能类似于：

a     { display: block; }
a img { display: block; }

使用适当的 CSS 选择器来本地化它们。

于 2011-04-17T01:55:15.670 回答