我在将类的对象放在无序映射中作为键时遇到问题,这是一个简单的示例:
class first
{
string name;
public:
first(){}
first(string nam):name(nam){}
string get_name() const
{
return name;
}
};
struct SampleTraits
{
size_t operator()(const first &that) const
{
return tr1::hash<const char*>()(that.get_name().c_str());
}
bool operator()(const first &t1,const first &t2) const
{
return t1.get_name()==t2.get_name();
}
};
typedef tr1::unordered_set<unsigned short> uset;
typedef tr1::unordered_map<first,uset,SampleTraits,SampleTraits> umap;
ostream& operator <<(ostream& out, uset &ust)
{
for(uset::iterator it=ust.begin();it!=ust.end();++it)
out<<" "<<*it;
}
int main()
{
umap *mymap= new umap;
string names,nm,n;
cout<<"\nEnter 1st name: ";
cin>>names;
first obj(names);
(*mymap)[obj].insert(100);
(*mymap)[obj].insert(120);
(*mymap)[obj].insert(112);
cout<<"\nEnter 2nd name:";
cin>>nm;
first obj2(nm);
(*mymap)[obj2].insert(201);
(*mymap)[obj2].insert(202);
cout<<"\nEnter name which u want to search:";
cin>>n;
first obj1(n);
umap::iterator it=mymap->find(obj1);
cout<<it->first.get_name();
cout<<it->second;
//delete mymap;
/*
for(umap::iterator it=mymap->begin();it!=mymap->end();it++)
{
cout<<it->first.get_name()<<" ";
cout<<it->second<<endl;
}
*/
return 0;
}
我的问题是当我尝试插入两个不同的对象并尝试显示它时显示分段错误..再次如果我尝试使用 find() 那么它也显示分段错误..我很难理解为什么 unordered_map 显示这种行为。
任何帮助将不胜感激!!这将对我的项目有很大帮助...