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考虑以下来自 XSD 的片段:

    <xs:complexType name="AccountIdentification4ChoiceGPS">
    <xs:choice>
        <xs:element name="IBAN" type="IBAN2007Identifier">
            <xs:annotation>
                <xs:appinfo>
                    <xs:logicalname>IBAN</xs:logicalname>
                    <xs:additionalInfo>[A-Z]{2,2}[0-9]{2,2}[a-zA-Z0-9]{1,30}</xs:additionalInfo>
                    <xs:ISOType>(CashAccount20)</xs:ISOType>
                </xs:appinfo>
                <xs:documentation>Unambiguous identification of the account as International Bank Account Number (IBAN).</xs:documentation>
            </xs:annotation>
        </xs:element>
        <xs:element name="Othr" type="GenericAccountIdentification1GPS">
            <xs:annotation>
                <xs:appinfo>
                    <xs:logicalname>Other</xs:logicalname>
                    <xs:ISOType>(CashAccount20)</xs:ISOType>
                </xs:appinfo>
            </xs:annotation>
        </xs:element>
    </xs:choice>
</xs:complexType>

使用 LINQ:如果我 对 XSD 的内容不太了解,我该element name="IBAN"如何检索元素 。`?<xs:complexType name="AccountIdentification4ChoiceGPS">我可能知道的唯一想法是 LocalName 是“complexType”;

我在想:

    IEnumerable<XElement> elementAbove = xsdDocument.Descendants()
.Where(x=>x.Name.LocalName == "complexType")
.Select(Get here the value of the element that could be the parent or the parent's parent).

这就是我卡住的地方。

4

1 回答 1

2

尝试:

IEnumerable<XElement> elementAbove = xsdDocument.Descendants()
   .Where(x => x.Name.LocalName == "complexType" && x.Descendants().Any(y => y.Name.LocalName == "element" && y.Attributes().Any(z => z.Value == "IBAN")));
于 2019-06-27T21:03:30.360 回答