1

尝试在 Loki JS 中动态添加他们拥有的人员和水果的条目，但我不断收到Trying to update unsynced document. Please save the document first by using insert() or addMany()错误消息。有人对如何成功地做到这一点有任何想法吗？

我已经记录了传入的值，它们与数据库中已经找到的值相匹配。

const loki = require('lokijs');

const db = new loki('loki.json');

const peopleAndFruits = db.addCollection('peopleAndFruits');

peopleAndFruits.insert({ dbname: 'person', fruits: 10 });

const createOrInsertUserToDb = (name, fruitNumber) => {
    const data = peopleAndFruits.find({ dbname: name });
    console.log('db entry before updated ', data[0].dbname);
    if (data[0].dbname !== name) {
        // console.log('this person did not exist in our database');
        peopleAndFruits.insert({ dbname: name, fruits: fruitNumber });
    } else {
        // console.log('previously existing entry');
        peopleAndFruits.update({
            dbname: data[0].dbname,
            fruits: Number(fruitNumber + data.fruits),
        });
    }
    // console.log('data after update or insert', peopleAndFruits.data);
    db.saveDatabase();
};
4

2 回答 2

3

我偶然发现了这个问题，问题是在调用时peopleAndFruits.update，您传递的文档需要是集合中的现有项目，这意味着它必须有一个$lokiid。在您的情况下，您可以选择

peopleAndFruits.update({
  ...data[0],
  fruits: +fruitNumber + fruits;
});

或者

peopleAndFruits.findAndUpdate({$loki: data[0].$loki}, item => {
  item.fruits = +fruitNumber + fruits;
});
于 2020-01-17T14:02:09.180 回答
3

您需要首先从集合中选择文档，最好通过其唯一 ID：

const loki = require('lokijs');

const db = new loki('loki.json');

const peopleAndFruits = db.addCollection('peopleAndFruits', {unique: '_id'});

peopleAndFruits.insert({_id:"spy_007", dbname: 'person', fruits: 10 });

let doc = peopleAndFruits.by("_id", 'spy_007') //select the doc first to be updated

doc.dbname = "John"  //update its values
doc.fruits = 100   //update its values

peopleAndFruits.update(doc) //update the collection
于 2020-11-16T12:31:00.233 回答