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我正在使用CosmosDB Graph 数据库来存储一些人的姓名、他们的婚姻以及他们在婚姻中拥有的孩子。在下图中，您将看到丈夫的第一次婚姻有一个孩子 A ，第二次婚姻有一个孩子 B。

       Father of Husband                 Mother of Husband        GRAND FATHER & GRAND MOTHER
                +---------------+--------------+
                            Marriage
                                |
   +------------+---------------+--------------+-----------+      FATHER & MOTHER
Ex Wife A   Marriage         Husband       Marriage      Wife B
                |                              |
            Child A                         Child B               ME & STEP BROTHERS

我想使用GremlinAPI生成如下所示的 JSON 输出，这是一个分层树结构。

如何将图形构造person为节点和边relationship以将图形转换为自定义 JSON 输出？

{
    "marriage": {
        "husband": {
            "name": "Father Of Husband"
        },
        "wife": {
            "name": "Mother Of Husband"
        }
    },
    "children": [
        {
            "marriage": {
                "husband": {
                    "name": "Husband"
                },
                "wife": {
                    "name": "Wife A"
                }
            },
            "children": [
                {
                    "marriage": {
                        "husband": {
                            "name": "Child A"
                        },
                        "wife": {
                            "name": "Unknown"
                        }
                    }
                }
            ]
        },
        {
            "marriage": {
                "husband": {
                    "name": "Husband"
                },
                "wife": {
                    "name": "Wife B"
                }
            },
            "children": [
                {
                    "marriage": {
                        "husband": {
                            "name": "Child B"
                        },
                        "wife": {
                            "name": "Unknown"
                        }
                    }
                }
            ]
        }
    ]
}

2019 年 6 月 21 日更新

我创建了以下查询来创建顶点和边：

g.V().drop()
g.addV('person').property(id, 'father_of_husband').property('name', 'Father Of Husband').property('title', 'husband')
g.addV('person').property(id, 'mother_of_husband').property('name', 'Mother Of Husband').property('title', 'wife')
g.addV('person').property(id, 'husband').property('name', 'Husband').property('title', 'husband')
g.addV('person').property(id, 'ex_wife_a').property('name', 'Ex Wife A').property('title', 'wife')
g.addV('person').property(id, 'wife_b').property('name', 'Wife B').property('title', 'wife')
g.addV('person').property(id, 'child_a').property('name', 'Child A').property('title', 'husband')
g.addV('person').property(id, 'child_b').property('name', 'Child B').property('title', 'wife')

g.addV('marriage').property(id, 'marriage_f_m').property('name', 'Marriage F & M')
g.addV('marriage').property(id, 'marriage_ex_wife_a_h').property('name', 'Marriage EWA & H')
g.addV('marriage').property(id, 'marriage_wife_b_h').property('name', 'Marriage WB & H')

g.V('father_of_husband').addE('married').to(g.V('marriage_f_m'))
g.V('mother_of_husband').addE('married').to(g.V('marriage_f_m'))

g.V('ex_wife_a').addE('married').to(g.V('marriage_ex_wife_a_h'))
g.V('husband').addE('married').to(g.V('marriage_ex_wife_a_h'))

g.V('wife_b').addE('married').to(g.V('marriage_wife_b_h'))
g.V('husband').addE('married').to(g.V('marriage_wife_b_h'))

g.V('husband').addE('child_of').to(g.V('marriage_f_m'))
g.V('child_a').addE('child_of').to(g.V('marriage_ex_wife_a_h'))
g.V('child_b').addE('child_of').to(g.V('marriage_wife_b_h'))
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1 回答 1

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我认为没有任何方法可以按照您描述的格式构建结果。最好的办法可能是：

  • 得到一棵包含所有关系的树
  • 在客户端处理此树并将其转换为所需的结构

要获得完整的树，您可以：

g.V('marriage_f_m').
  repeat(__.both().simplePath()).
    emit().
  tree()

...或包含边缘标签以简化重组：

g.V('marriage_f_m').
  repeat(__.bothE().otherV().simplePath()).
    emit().
  tree().
    by().
    by(label)
于 2019-06-24T15:45:10.477 回答