我遇到了一个问题,我的输出中出现了一些不正确的值。我将下面突出显示的表格列与底部的圆圈列绑定。突出显示的列上的 service_id 是唯一的,但我需要绑定 booking_id 来检索信息(如果这有意义的话。我最终得到的是我得到重复的顶层表,或者价格是错误的。我应该在顶部表格中仅获得 5 行。
这是我的代码。我怀疑我可能做错了加入?
SELECT bad.agent as Agents,
dog.SUPPLIER as SUPPLIER,
bad.status as TheStatus,
country.analysis_master1 as Country,
ftb.booking_actual_retail as BookingActualRetail,
ftb.Booking_Actual_Cost as BookingCost,
ftb.Booking_Actual_Retail_inc as BookingRetailINC,
fts.Service_Id,
fts.Service_Actual_Retail_inc as ServiceActualCostInc,
Product.SERVICE,
Product.SL_STATUS as SLSTATUS,
cat.name as Product2,
bad.LAST_SERVICE_DATE as Servicedate,
bad.LW_DATE as LWDATE,
ftb.Entered_Date as DATEENTERED,
ftb.Booking_Pax as PEOPLE,
ftb.Booking_Children as KIDS,
bad.TRAVELDATE as TRAVELDATE,
bad.FULL_REFERENCE
from BHD bad
inner join FTB on bad.FULL_REFERENCE = ftb.booking_reference
inner join FTS on FTB.Booking_Id = fts.Booking_Id
inner join DRM Country on bad.agent = country.code
inner join BSL Product on bad.BHD_ID = Product.BHD_ID
inner join SRV cat on Product.SERVICE = cat.CODE
inner join OPT dog on Product.OPT_ID = dog.OPT_ID
where bad.STATUS = 'IV' AND bad.FULL_REFERENCE = 'LTIT129488'
更新:
好的,所以看起来这里的连接会导致多个输出:
inner join FTS on FTB.Booking_Id = fts.Booking_Id
我已经包含了这两个表、它们的标题和示例数据