Yes, you should write:
const std::string& getString() const noexcept { return someString; }
Instead of (note: not const
, because never return const
values):
std::string_view getString() const noexcept { return someString; }
The reason is - you already have a string
. So it's not like you have to pay anything extra to get a string
out of it. And string
has one notable semantic difference to an arbitrary string_view
: it's null-terminated by guarantee. We know this. Maybe some downstream user needs to rely on that information. If they need null-termination (e.g. they need to pass to some C API that requires it) and you give a string_view
, they have to make a string
out of it themselves. You save nothing, but potentially make downstream users do more work.
If, however, you had a vector<char>
instead... then I would suggest to return a span<char const>
or the equivalent thereof. Since there is no semantic difference and you're just providing a view.
There also the separate argument of what:
auto x = obj.getString();
should do. This either takes a copy of the string
(expensive, but safe) or effectively a reference to it (cheap, but potentially dangling). But it doesn't entirely look like a reference, it looks like a value. This is a broad issue with reference-semantic types in general (things like reference_wrapper
, string_view
, span
, tuple<T&...>
, optional<T&>
if it existed, etc.).
I don't have an answer for this case, but it's something to be aware of.