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我在通过存储过程将数据插入表中时遇到了一些麻烦。请允许我详细解释。

我有一张三张桌子

CREATE TABLE `table_1` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `s_id` INT(11) NOT NULL,
    `created` DATE NOT NULL,    
    `val` VARCHAR(255) NOT NULL,    
    PRIMARY KEY (`id`)

)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
AUTO_INCREMENT=1;

 CREATE TABLE `table_2` (
    `s_id` INT(11) NOT NULL AUTO_INCREMENT,
    `t_id` INT(11) NOT NULL,
    `p_id` INT(11) NOT NULL,
    `d_id` INT(11) NOT NULL,
    `created` DATE NOT NULL,    

    PRIMARY KEY (`id`)

)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
AUTO_INCREMENT=1;

CREATE TABLE `table_3` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `count` INT(11) NOT NULL,
    `created` DATE NOT NULL,    
    `s_id` VARCHAR(255) NOT NULL,
    `t_id` VARCHAR(255) NOT NULL,   
    `p_id` VARCHAR(255) NOT NULL,   
    PRIMARY KEY (`id`)

)

有没有办法使用 select 语句通过存储过程插入第二个表。会有多个数据为Select * from table_1; 然后会有一个像if(table_1.s_id == table_3.s_id) THEN UPDATE table_3 set count = count +1 ELSE INSERT into table_3(s_id,t_id.....

虽然我尝试过使用 Cursor 但它只插入一条记录。

这是我使用光标的示例

DECLARE done INT DEFAULT FALSE; 
DECLARE curs_count INT(11) DEFAULT 0;

DECLARE v_s_id BIGINT(20) DEFAULT 0;
DECLARE v_t_id BIGINT(20) DEFAULT 0;
DECLARE v_p_id BIGINT(20) DEFAULT 0;
DECLARE v_t_date BIGINT(20) DEFAULT 0;
DECLARE co_s_id BIGINT(20) DEFAULT 0;

DECLARE curs CURSOR FOR
SELECT 
    a.id,b.s_id,b.t_id,b.created
    FROM 
        table_1 a 
        INNER JOIN table_2 b ON a.s_id =  b.s_id        
    WHERE 
        a.val <> '';        
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
DECLARE curs_id INT(11) DEFAULT 0;

OPEN curs;
  SELECT FOUND_ROWS() INTO curs_count; 
 start_loop: loop
     FETCH curs INTO curs_id,v_s_id,v_t_id,v_c_date;    
     IF done THEN
     LEAVE start_loop;
     END IF;

     SELECT s_id INTO co_s_id FROM table_3;

     IF co_s_id>0
     THEN
     update table_3 SET count = count+1 where s_id = co_s_id;
     ELSE
     INSERT INTO table_3 (support_id,track_id,track_date,count) VALUES (v_s_id,v_t_id,v_c_date,1);
     END IF;
    end loop;
    CLOSE curs; 

谁能帮我解决这个问题?

4

1 回答 1

0

此代码运行正常。问题是无限循环使表损坏,因此没有数据插入。

于 2019-06-17T05:45:08.567 回答