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我对 OPENJSON 没有太多经验，我尝试使用这些示例，但我无法解析下面的字符串

任何人都可以帮助我。

我希望它采用以下格式：

Date,TimeSheet.StartTime,TimeSheet.FinishTime,Timesheet.BreakStart,TimeSheet.BreakFinish,Timesheet.EmployeeId,TimeSheet.Notes

[
{
    "Date": "0001-01-01T00:00:00+00:00",
    "TimeSheet": [
        {
            "StartTime": "0001-01-01T00:00:00+00:00",
            "FinishTime": "0001-01-01T00:00:00+00:00",``
            "BreakTimes": [
                "0001-01-01T00:00:00+00:00",
                "0001-01-01T00:00:00+00:00"
            ],
            "EmployeeId": 1,
            "Notes": "Blah, blah, blah..."
        }
    ]
},
{
    "Date": "0001-01-01T00:00:00+00:00",
    "TimeSheet": [
        {
            "StartTime": "0001-01-01T00:00:00+00:00",
            "FinishTime": "0001-01-01T00:00:00+00:00",
            "BreakTimes": [
                "0001-01-01T00:00:00+00:00",
                "0001-01-01T00:00:00+00:00"
            ],
            "EmployeeId": 1,
            "Notes": "Blah, blah, blah..."
        }
    ]
}    
]

这是我尝试使用的代码：

DECLARE @json NVARCHAR(MAX)
DECLARE @json2 NVARCHAR(MAX)

SET @json= (Select [TimeSheetTestData] FROM [TimeSheetTestData] WHERE [TimeSheetTestDataId] = 3) -- this is the sample json above

SET @json2=(SELECT Value
FROM OpenJson(@json) where [Key] = 'TimeSheet')

--SELECT [Key], Value
--FROM OpenJson(@json2)

SELECT * FROM  
OPENJSON ( @json2 )  
WITH (   
              startTime   varchar(200) '$.StartTime' ,
              finishTime   varchar(200) '$.FinishTime' ,
              breakTimes   varchar(200) '$.BreakTimes' ,
              employeeId   varchar(200) '$.EmployeeId' ,
              notes   varchar(200) '$.Notes' 
 )
4

1 回答 1

0

您需要做的是将OPENJSON()与显式模式和CROSS APPLY运算符一起使用。

输入：

DECLARE @json nvarchar(max) = N'
[
{
    "Date": "0001-01-01T00:00:00+00:00",
    "TimeSheet": [
        {
            "StartTime": "0001-01-01T00:00:00+00:00",
            "FinishTime": "0001-01-01T00:00:00+00:00",
            "BreakTimes": [
                "0001-01-01T00:00:00+00:00",
                "0001-01-01T00:00:00+00:00"
            ],
            "EmployeeId": 1,
            "Notes": "Blah, blah, blah..."
        }
    ]
},
{
    "Date": "0001-01-01T00:00:00+00:00",
    "TimeSheet": [
        {
            "StartTime": "0001-01-01T00:00:00+00:00",
            "FinishTime": "0001-01-01T00:00:00+00:00",
            "BreakTimes": [
                "0001-01-01T00:00:00+00:00",
                "0001-01-01T00:00:00+00:00"
            ],
            "EmployeeId": 1,
            "Notes": "Blah, blah, blah..."
        }
    ]
}    
]'

T-SQL：

SELECT 
   j1.[Date], j2.StartTime, j2.FinishTime, j2.BreakStart, j2.BreakFinish, j2.EmployeeId, j2.Notes
FROM OPENJSON(@json)
WITH (
   [Date] nvarchar(25) '$.Date',
   TimeSheet nvarchar(max) '$.TimeSheet' AS JSON
) j1
CROSS APPLY OPENJSON(j1.TimeSheet) 
WITH (
   StartTime nvarchar(25) '$.StartTime',
   FinishTime nvarchar(25) '$.FinishTime',
   BreakStart nvarchar(25) '$.BreakTimes[0]',
   BreakFinish nvarchar(25) '$.BreakTimes[1]',
   EmployeeId int '$.EmployeeId',
   Notes nvarchar(max) '$.Notes'
) j2

输出：

Date                        StartTime                   FinishTime                  BreakStart                  BreakFinish                 EmployeeId  Notes
0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   1           Blah, blah, blah...
0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   0001-01-01T00:00:00+00:00   1           Blah, blah, blah...

更新：

如果您的 JSON 始终包含"TimeSheet"JSON 数组中的一项，则下一条语句也是一种选择：

SELECT 
   j.[Date], 
   j.StartTime,
   j.FinishTime,
   j.BreakStart,
   j.BreakFinish,
   j.EmployeeId,
   j.Notes
FROM OPENJSON(@json)
WITH (
   [Date] nvarchar(25) '$.Date',
   StartTime nvarchar(25) '$.TimeSheet[0].StartTime',
   FinishTime nvarchar(25) '$.TimeSheet[0].FinishTime',
   BreakStart nvarchar(25) '$.TimeSheet[0].BreakTimes[0]',
   BreakFinish nvarchar(25) '$.TimeSheet[0].BreakTimes[1]',
   EmployeeId int '$.TimeSheet[0].EmployeeId',
   Notes nvarchar(max) '$.TimeSheet[0].Notes'
) j
于 2019-06-03T07:05:30.577 回答