我想将我的数据保存在 .txt 文件中。在另一个活动中,我希望能够读取保存的数据。我想每次保存多个值并将它们放在一行中,下一个值需要在新行中。我尝试\n System.getProperty("line.separator"); System.lineSeparator();并\n\r从新行开始,但这似乎不起作用,而数据仍然彼此落后而不是在另一行上。
我使用此代码写入文件:
Context context = getApplicationContext();
writedatatofile(context);
protected void writedatatofile(Context context){
try
{
OutputStreamWriter outputStreamWriter = new OutputStreamWriter(context.openFileOutput("data_log.txt", Context.MODE_APPEND));
String data;
if (newstart){
data = "Exersice started \n" + "t.s a.s t.a a.a cnst";
} else {
data = (Integer.toString(time_step)+Integer.toString(new_average_step)+Integer.toString(time_footaid)+Integer.toString(new_average_aid)+Boolean.toString(rhythmconsistent)+"\n");
}
outputStreamWriter.append(data);
outputStreamWriter.close();
Toast.makeText(this, "Data has been written to File", Toast.LENGTH_SHORT).show();
}
catch(IOException e) {
e.printStackTrace();
}
}
和这段代码来读取文件:
Context context = getApplicationContext();
String fileData = readFromFile(context, fileName);
TextView datalog = findViewById(R.id.datalog);
datalog.setText(fileData);
private String readFromFile(Context context, String fileName){
String ret = " ";
try {
InputStream inputStream = context.openFileInput(fileName);
if (inputStream != null) {
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
String receiveString = "";
StringBuilder stringBuilder = new StringBuilder();
while ((receiveString = bufferedReader.readLine()) != null) {
Toast.makeText(this, "Data received", Toast.LENGTH_SHORT).show();
stringBuilder.append(receiveString);
}
inputStream.close();
ret = stringBuilder.toString();
} else {
Toast.makeText(this, "No data received", Toast.LENGTH_SHORT).show();
}
} catch (FileNotFoundException e){
Toast.makeText(this, "File not found", Toast.LENGTH_SHORT).show();
} catch (IOException e){
Toast.makeText(this, "Can not read file", Toast.LENGTH_SHORT).show();
}
return ret;
}
如前所述,“\n”并没有解决问题,但也没有出现在我的数据中作为 \n。因此它不会存储为普通字符串。