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我有一个用 Pygame 制作的游戏，我添加了一个“小”更新，当按下空格键时，一个精灵会在 80 毫秒内变为另一个精灵，这会使整个游戏滞后（不仅仅是在按下空格键时，而是一直）。任何人都可以帮忙吗？:)

这是“更新”之前的一些代码：

人.py

class Man(Sprite):
    def __init__(self, ai_settings, screen):
        super().__init__()
        self.screen = screen

        # Load the image of the man and get its rect.
        self.image = pygame.image.load('images/man_gun_large.bmp')
        self.rect = self.image.get_rect()
        self.screen_rect = screen.get_rect()

        # Man firing gun sprite
        self.fire = pygame.image.load('images/man_gun_large_fire.bmp')
        self.fire_rect = self.fire.get_rect()
        self.screen_fire_rect = self.screen.get_rect()

        self.ai_settings = ai_settings

        # Start each new man at the bottom center of the screen.
        self.rect.centerx = self.screen_rect.centerx
        self.rect.bottom = self.screen_rect.bottom

        self.fire_rect.centerx = self.screen_rect.centerx
        self.fire_rect.top = self.screen_rect.bottom

        # Store a decimal value for the man's center.
        self.center = float(self.rect.centerx)

        # Movement flags
        self.moving_right = False
        self.moving_left = False

        self.orientation = False

    def update(self):
        # Update the man's center value, not the rect
        if self.moving_right and self.rect.right < self.screen_rect.right:
            self.center += self.ai_settings.man_speed_factor
        if self.moving_left and self.rect.left > 0:
            self.center -= self.ai_settings.man_speed_factor

        # Update rect object from self.center.
        self.rect.centerx = self.center

    def blitme(self):
        # Draw sprite
        self.screen.blit(self.image, self.rect)

        # Flip sprite depending on right/left key
        if self.orientation == "Right":
            self.screen.blit(self.image, self.rect)
        elif self.orientation == "Left":
            self.screen.blit(pygame.transform.flip(self.image, True, False), 
            self.rect)

游戏功能.py

def fire_bullet(ai_settings, bullets, screen, man):
    # Fire a bullet as long as max bullets is not reached
    # Create a new bullet and add it to the bullets group.
    if len(bullets) < ai_settings.bullets_allowed:
        fire_sound.play()
        new_bullet = Bullet(ai_settings, screen, man)
        bullets.add(new_bullet)

这是“更新”之后的相同代码：

人.py

class Man(Sprite):
    # --- SNIP ---

        # A field to keep track of timeout
        self.timeout = 0

    def update(self):
        # --- SNIP ---

        clock = pygame.time.Clock()
        dt = clock.tick(60)

        if self.timeout > 0:
            self.timeout = max(self.timeout - dt, 0)

    def blitme(self):
        # --- SNIP ---

        # Change into firesprite when pressing space
        elif self.timeout > 0 and self.orientation == 'Right':
            self.screen.blit(self.fire, self.rect)
        elif self.timeout > 0 and self.orientation == 'Left':
            self.screen.blit(pygame.transform.flip(self.fire, True, False), 
            self.rect)

游戏功能.py

def fire_bullet(ai_settings, bullets, screen, man):
    # --- SNIP ---
        man.timeout = 80
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1 回答 1

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对象的方法tick()以pygame.time.Clock这种方式延迟游戏，循环的每次迭代消耗相同的时间段。见pygame.time.Clock.tick()：

此方法应每帧调用一次。

您需要clock.tick(60)每帧调用一次，而不是为每个更新的对象调用一次。如果您有多个对象，则每帧将多次调用该方法，并且游戏会随着对象数量的增加而变慢。

于 2020-12-26T17:51:40.907 回答