xml - 使用 Python 解析 XML

Question

我正在使用 Python 2.5 和 WinXP。我正在解析 xml 文件，如下所示：

<Test>
<Default_Config>
  <LINK>{1: 1, 2: 2, 3: 3, 4: 4, 5: 5, 6: 6}</LINK> 
  <Lanestat>{1: 2, 2: 4, 3: 6, 4: 8, 5: 10, 6: 12}</Lanestat> 
  </Default_Config>
  </Test>

但是当我打印出来时，输出如下：

(None, '{1: 1, 2: 2, 3: 3, 4: 4, 5: 5, 6: 6}')
(None, '{1: 2, 2: 4, 3: 6, 4: 8, 5: 10, 6: 12}')

问题：如何修改我的代码，使 Link 和 Lanestat 出现而不是 None。tq 代码：

import elementtree.ElementTree as ET

tree = ET.parse("dict1.xml")
doc = tree.getroot()


for elem in doc.findall('Default_Config/LINK'):
    #print elem.get('LINK'), elem.text
    a=elem.get('LINK'), elem.text
    print a

for elem in doc.findall('Default_Config/Lanestat'):

    #print elem.get('LINK'), elem.text
    a=elem.get('LINK'), elem.text
    print a

Answer 1

import xml.etree.ElementTree as ET

tree = ET.parse("dict1.xml")
doc = tree.getroot()

for elem in doc.findall('Default_Config/LINK'):
    a = elem.tag, elem.text
    print a

for elem in doc.findall('Default_Config/Lanestat'):
    a = elem.tag, elem.text
    print a

=>

('LINK', '{1: 1, 2: 2, 3: 3, 4: 4, 5: 5, 6: 6}')
('Lanestat', '{1: 2, 2: 4, 3: 6, 4: 8, 5: 10, 6: 12}')

Answer 2

尝试使用 a=elem.tag 而不是 a=elem.get('LINK')

import elementtree.ElementTree as ET

tree = ET.parse("dict1.xml")
doc = tree.getroot()

for elem in doc.findall('Default_Config/LINK'):
    a=elem.tag, elem.text
    print a

for elem in doc.findall('Default_Config/Lanestat'):
    a=elem.tag, elem.text
    print a