我正在尝试运行 zookeeper 合奏,但在将唯一 ID 作为环境变量传递时遇到问题,这是此处ZOO_MY_ID
找到的官方 zookeeper 图像所要求的。
我已经尝试阅读此内容并发现类似的溢出问题,但似乎没有一个有效。
kubernetes statefulsets index/ordinal 在模板中公开 有没有办法在 kubernetes statefulset 配置文件中获取 pod 的序数索引?
出于某种原因,我仍然看到所有服务器的 ID 都是默认 ID 1
2019-05-24 01:38:31,648 [myid:1] - INFO [QuorumPeer[myid=1]/0:0:0:0:0:0:0:0:2181:FastLeaderElection@847] - Notification time out: 60000
2019-05-24 01:38:31,649 [myid:1] - INFO [WorkerSender[myid=1]:QuorumCnxManager@347] - Have smaller server identifier, so dropping the connection: (2, 1)
2019-05-24 01:38:31,649 [myid:1] - INFO [WorkerReceiver[myid=1]:FastLeaderElection@595] - Notification: 1 (message format version), 1 (n.leader), 0x0 (n.zxid), 0x1 (n.round), LOOKING (n.state), 1 (n.sid), 0x0 (n.peerEpoch) LOOKING (my state)
2019-05-24 01:38:31,649 [myid:1] - INFO [/0.0.0.0:3888:QuorumCnxManager$Listener@743] - Received connection request /10.24.1.64:37382
2019-05-24 01:38:31,650 [myid:1] - WARN [RecvWorker:1:QuorumCnxManager$RecvWorker@1025] - Connection broken for id 1, my id = 1, error =
java.io.EOFException
at java.io.DataInputStream.readInt(DataInputStream.java:392)
at org.apache.zookeeper.server.quorum.QuorumCnxManager$RecvWorker.run(QuorumCnxManager.java:1010)
2019-05-24 01:38:31,651 [myid:1] - WARN [RecvWorker:1:QuorumCnxManager$RecvWorker@1028] - Interrupting SendWorker
运行以下命令显示没有传递任何 ID,但是我使用的是此处显示的 hacky 方式:https ://stackoverflow.com/a/48086813/5813215
kubectl exec -it zoo-2 -n kafka-dev printenv | grep "ZOO_"
ZOO_USER=zookeeper
ZOO_CONF_DIR=/conf
ZOO_DATA_DIR=/data
ZOO_DATA_LOG_DIR=/datalog
ZOO_LOG_DIR=/logs
ZOO_PORT=2181
ZOO_TICK_TIME=2000
ZOO_INIT_LIMIT=5
ZOO_SYNC_LIMIT=2
ZOO_AUTOPURGE_PURGEINTERVAL=0
ZOO_AUTOPURGE_SNAPRETAINCOUNT=3
ZOO_MAX_CLIENT_CNXNS=60