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我将如何记录Swagger的InputStream路径参数?List<Person>ApiPath 似乎没有 request 和 requestContainer 参数。提前致谢。


    @POST
    @Path("/V1/person/batch")
    public void postPersonBatch(InputStream in) throws IOException {
        try (MappingIterator<Person> people = reader.readValues(in)) {
            people.forEachRemaining(writer::write);
        }
    }
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