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我有一个这样的文本块：

var a = [
  {"id": 1, "name": "Name 1", "description": "Description for item #1"},
  {"id": 2, "name": "Name 2", "description": "Description for item #2"},
  {"id": 4, "name": "Name 4", "description": "Description for item #4"},
  {"id": 5, "name": "Name 5", "description": "Description for item #5"},
  {"id": 6, "name": "Name 6", "description": "Description for item #6"},
  {"id": 7, "name": "Name 7", "description": "Description for item #7"},
  {"id": 8, "name": "Name 8", "description": "Description for item #8"},
  {"id": 9, "name": "Name 9", "description": "Description for item #9"},
  {"id": 10, "name": "Name 10", "description": "Description for item #10"},
  {"id": 11, "name": "Name 11", "description": "Description for item #11"},
  {"id": 12, "name": "Name 12", "description": "Description for item #12"},
  {"id": 13, "name": "Name 13", "description": "Description for item #13"},
  {"id": 14, "name": "Name 14", "description": "Description for item #14"},
  {"id": 15, "name": "Name 15", "description": "Description for item #15"},
]

我想在列表的所有对象成员中添加一个“lastName”项，它们应该变成这样：

var a = [
  {"id": 1, "name": "Name 1", "lastName": "Last Name 1", "description": "Description for item #1"},
  {"id": 2, "name": "Name 2", "lastName": "Last Name 2", "description": "Description for item #2"},
  {"id": 4, "name": "Name 4", "lastName": "Last Name 4", "description": "Description for item #4"},
  {"id": 5, "name": "Name 5", "lastName": "Last Name 5", "description": "Description for item #5"},
  {"id": 6, "name": "Name 6", "lastName": "Last Name 6", "description": "Description for item #6"},
  {"id": 7, "name": "Name 7", "lastName": "Last Name 7", "description": "Description for item #7"},
  {"id": 8, "name": "Name 8", "lastName": "Last Name 8", "description": "Description for item #8"},
  {"id": 9, "name": "Name 9", "lastName": "Last Name 9", "description": "Description for item #9"},
  {"id": 10, "name": "Name 10", "lastName": "Last Name 10", "description": "Description for item #10"},
  {"id": 11, "name": "Name 11", "lastName": "Last Name 11", "description": "Description for item #11"},
  {"id": 12, "name": "Name 12", "lastName": "Last Name 12", "description": "Description for item #12"},
  {"id": 13, "name": "Name 13", "lastName": "Last Name 13", "description": "Description for item #13"},
  {"id": 14, "name": "Name 14", "lastName": "Last Name 14", "description": "Description for item #14"},
  {"id": 15, "name": "Name 15", "lastName": "Last Name 15", "description": "Description for item #15"},
]

我的宏是这个

:reg l
--- Registers ---
"l   0f:2lyiw2f,a "lastName": "Last Name 0",^[2hmi2F,hyiw`iviw"0p

并且可以在一行中正常工作，或者如果我j在末尾附加 a 以向下移动并像14@l.

我不能做的是用 视觉选择所有行V，然后输入:normal @l，因为它只适用于选择的第一行（无论j最后是否附加了 a ）。如何使它在所有选定的行中工作？

4

1 回答 1

2

一旦您选择了线路，您需要这样做：

:'<,'>norm @l

在所有选定的行中执行。:normal @l仅在当前行执行。

此外，您可以直接给出一系列行（而不是进入可视模式）：

:10,20norm @l

您要覆盖的范围的第一行和最后一行在哪里10以及在哪里。20

另外，您还可以在与模式匹配的所有行上运行宏：

:g/"name"/norm @l

在所有匹配的行上执行宏"name"

于 2019-05-16T14:58:17.323 回答