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我正在尝试创建一个字符串列表，该列表在邮箱处理器的帮助下逐渐异步插入元素。但是我没有得到想要的输出。

我几乎遵循了https://fsharpforfunandprofit.com/posts/concurrency-actor-model/中的代码， 但是在我的情况下它似乎没有按预期工作。我的代码如下：

type TransactionQueue ={

queue : string list

} with

static member UpdateState (msg : string) (tq : TransactionQueue) =
    {tq with queue = (msg :: tq.queue)}

static member Agent = MailboxProcessor.Start(fun inbox ->
                            let rec msgLoop (t : TransactionQueue) =
                                async{
                                   let! msg = inbox.Receive()
                                   let newT = TransactionQueue.UpdateState msg t
                                   printfn "%A" newT
                                   return! msgLoop newT
                                }
                            msgLoop {queue = []}
                        )

static member Add i = TransactionQueue.Agent.Post i



[<EntryPoint>]
let main argv =

// test in isolation
printfn "welcome to test"
let rec loop () =
    let str = Console.ReadLine()
    TransactionQueue.Add str
    loop ()

loop ()



0

我不断得到的结果只是最新输入的列表，不保留状态。所以如果我输入“a”然后“b”然后“c”队列将只有值“c”而不是“a”;“b”;“c”

任何帮助或指示将不胜感激！

4

1 回答 1

2

就像C# Properties一样，您Agent实际上是一个 Property，因此其行为类似于带void参数的方法。这就是为什么每次Agent访问属性时都会获得一个新代理的原因。

在惯用的 F# 中，实现代理时有两种样式。如果你不需要有很多代理实例，只需编写一个模块并将代理相关的东西封装在里面。否则，应使用 OOP 样式。

样式 #1 的代码

module TransactionQueue =
    type private Queue = Queue of string list
    let private empty = Queue []
    let private update item (Queue items) = Queue (item :: items)
    let private agent = MailboxProcessor.Start <| fun inbox ->
        let rec msgLoop queue = async {
            let! msg = inbox.Receive ()
            return! queue |> update msg |> msgLoop
        }
        msgLoop empty
    let add item = agent.Post item

[<EntryPoint>]
let main argv =
    // test in isolation
    printfn "welcome to test"
    let rec loop () =
        let str = Console.ReadLine()
        TransactionQueue.add str
        loop ()
    loop ()

样式 #2 的代码

type Queue = Queue of string list with
    static member Empty = Queue []
    static member Update item (Queue items) =
        Queue (item :: items)

type Agent () =
    let agent = MailboxProcessor.Start <| fun inbox ->
        let rec msgLoop queue = async {
            let! msg = inbox.Receive ()
            return! queue |> Queue.Update msg |> msgLoop
        }
        msgLoop Queue.Empty
    member this.Add item = agent.Post item

[<EntryPoint>]
let main argv =
    // test in isolation
    printfn "welcome to test"
    let agent = new Agent ()
    let rec loop () =
        let str = Console.ReadLine()
        agent.Add str
        loop ()
    loop ()

请注意对类型使用单例联合类型Queue。

于 2019-05-12T04:08:23.507 回答