powershell - 为什么PowerShell创建的线程不能执行脚本函数？

Question

我有一个调用的脚本函数。net 来操作word文档。有用。现在我想创建一个子线程来执行它，然后主线程决定它是否完成或超过指定时间，并在该时间之后结束它。如代码所示，它不执行$node代码块中的函数，而是$task1执行cmdlet。这是为什么？我怎样才能满足我的需求？

try{
# $cb is a instance of class，scan is the function I want to invoke.
    $code = { $cb.Scan($PrepareFileName, $NailDirName, $HtmlFileName) }
#    $task1 = { Start-Sleep -Seconds 9; Get-Service }
    $newThread = [PowerShell]::Create().AddScript($code)
    $handleTh = $newThread.BeginInvoke()
    $nTimes = 0;
    do
    {
        $nTimes++;
        if($handleTh.IsCompleted -or $nTimes -gt 10)
        {
          break;  
        }
        Start-Sleep -Milliseconds 500

    } while($true)

    $newThread.EndInvoke($handleTh)
    $newThread.Runspace.Close()
    $newThread.Dispose()

}catch{

}

Answer 1

您需要创建一个runspace和它到 PowerShell 对象。检查此微软“教程”以正确方式使用运行空间。该链接还解释了如何使用运行空间池和脚本块参数。

try{
    # $cb is a instance of class，scan is the function I want to invoke.
    $code = { 
        # Update 1, added parameter
        param($cb)
        $cb.Scan($PrepareFileName, $NailDirName, $HtmlFileName) 
    }
    # Create a runspace
    $runspace = [runspacefactory]::CreateRunspace()
    # Update 1, inject parameter
    $newThread = [PowerShell]::Create().AddScript($code).AddParameter(‘cb’,$callback)

    # Add the runspace
    $newThread.Runspace = $runspace
    $runspace.Open()
    $handleTh = $newThread.BeginInvoke()
    $nTimes = 0;
    do
    {
        $nTimes++;
        if($handleTh.IsCompleted -or $nTimes -gt 10)
        {
          break;  
        }
        Start-Sleep -Milliseconds 500

    } while($true)

    $newThread.EndInvoke($handleTh)
    $newThread.Dispose()
}
catch{
}

希望有帮助。