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我的线性插值有一些逻辑错误，它适用于某些情况但不完全有效。

我尝试使用不同的方式来编写外推案例的逻辑。

def interpolate(x, y, x_test):
    for i in range(len(x)):
        if x[i] > x_test:   #extrapolated condition: when the largest value of
            x_below = i - 1 #list x is greater than x_test 
            x_above = i 
            y_below = i - 1
            y_above = i
            break
        elif x[i] < x_test: #extrapolated condition: when the largest value of 
            x_below = i + 1 #list x is greater than x_test 
            x_above = i 
            y_below = i + 1
            y_above = i
            break                
        else:             #interpolated condition: when x_test lies between  
            return y[i]    #two sample points.

    #a = (yabove - ybelow) / (xabove - xbelow)         
    a = (y[y_above] - y[y_below]) / (x[x_above] - x[x_below])  
    #b = ybelow - a * xbelow
    b = y[y_below] - a * x[x_below]
    #y’ = a * x’ + b
    return a * x_test + b

interpolate([1, 3, 5], [1, 9, 25], 5.0) 我预计输出为 25，但实际输出为 17.0。

4

1 回答 1

0

我想你正在寻找这样的东西：

def interpolate(x, y, x_test):
    for i in range(len(x)):
        if x[i] > x_test:   #extrapolated condition: when the largest value of
            x_below = i - 1 #list x is greater than x_test
            x_above = i
            y_below = i - 1
            y_above = i
            continue # <---- I changed break to continue
        elif x[i] < x_test: #extrapolated condition: when the largest value of
            x_below = i + 1 #list x is greater than x_test
            x_above = i
            y_below = i + 1
            y_above = i
            continue # <---- I changed break to continue
        else:             #interpolated condition: when x_test lies between
            return y[i]    #two sample points.

    #a = (yabove - ybelow) / (xabove - xbelow)
    a = (y[y_above] - y[y_below]) / (x[x_above] - x[x_below])
    #b = ybelow - a * xbelow
    b = y[y_below] - a * x[x_below]
    #y’ = a * x’ + b
    return (a * x_test + b)

print(interpolate([1, 3, 5], [1, 9, 25], 5.0))

输出：

25

请注意，我将其更改breaks为continues.

于 2019-05-07T04:05:57.557 回答