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我正在尝试编写一个 glob 模式,它将搜索 intellij 二进制文件(大致),但不在 C:\Windows 内搜索,因为那里不太可能有任何内容。我添加了一堆似乎按预期工作的 minimatch 示例,但 glob.sync 没有找到该文件。任何帮助是极大的赞赏!

var minimatch = require("minimatch")
var globSync = require('glob').sync

const FILE_THAT_EXISTS = 'C:/Program Files/JetBrains/IntelliJ IDEA 2019.1.1/bin/idea64.exe';

const globPattern = `C:/!(Windows)/JetBrains/IntelliJ*/bin/idea64.exe`;

console.log(minimatch("C:/Program Files/JetBrains/IntelliJ IDEA 2019.1.1/bin/idea64.exe", globPattern))
console.log(minimatch("C:/Program Files (x86)/JetBrains/IntelliJ IDEA 2019.1.1/bin/idea64.exe", globPattern))
console.log(minimatch("C:/Windows/JetBrains/IntelliJ IDEA 2019.1.1/bin/idea64.exe", globPattern))
console.log(minimatch("C:/Software/JetBrains/IntelliJ IDEA 2019.1.1/bin/idea64.exe", globPattern))
console.log(minimatch(FILE_THAT_EXISTS, globPattern));

console.log('\n')

const globResults = globSync(globPattern, {})

console.log(`glob results:`)
console.log(globResults);

console.log('\n')

// Verify that file actually exists:

var fs = require('fs');

try {
    fs.accessSync(FILE_THAT_EXISTS)
    console.log('file found');
} catch (e) {
    console.log('file NOT found')
    console.error(e)
}

此脚本的输出:

true
true
false
true
true


glob results:
[]


file found

当然,我希望该可执行文件列在 globResults 数组中。

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1 回答 1

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这最终成为我想要的:

var globSync = require('glob').sync

const globPattern = `/!(windows)/jetbrains/intellij*/bin/idea64.exe`;

const globResults = globSync(globPattern, { nocase: true, strict: false,  silent: true })

console.log(`glob results:`, globResults)
于 2019-08-21T13:50:02.940 回答