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我一直在使用atom 1.36.1运行python3（3.7.3）代码

我突然收到以下错误信息

Traceback (most recent call last): 
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/runpy.py", line 193, in _run_module_as_main "main", mod_spec) 
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/runpy.py", line 85, in _run_code exec(code, run_globals) 
File "/usr/local/lib/python3.7/site-packages/ipykernel_launcher.py", line 15, in from ipykernel import kernelapp as app File "/usr/local/lib/python3.7/site-packages/ipykernel/init.py", line 2, in from .connect import * 
File "/usr/local/lib/python3.7/site-packages/ipykernel/connect.py", line 13, in from IPython.core.profiledir import ProfileDir 
File "/usr/local/lib/python3.7/site-packages/IPython/init.py", line 54, in from .core.application import Application 
File "/usr/local/lib/python3.7/site-packages/IPython/core/application.py", line 18, in import logging
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/logging/init.py", line 28, in from string import Template ImportError: cannot import name 'Template' from 'string' (/Users/mymac/Downloads/string.py)

这是 jupyter 内核 json 文件的内容：

{
 "argv": [
  "/usr/local/Cellar/python/3.7.3/bin/python3",
  "-m",
  "ipykernel_launcher",
  "-f",
  "{connection_file}"
 ],
 "display_name": "Python 3",
 "language": "python"
}

我究竟做错了什么？

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1 回答 1

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好的，我发现了问题：我创建了一个文件string.py(in /Users/mymac/Downloads/string.py)，该文件的名称与该文件使用的另一个文件相同/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/logging/init.py

我删除了这个string.py，这解决了问题

于 2019-05-04T15:50:05.480 回答