当我直接将数据输入到我的函数中时，我得到了正确的输出，但是当我使用来自用户的输入来填充列表时，什么也没有发生。我没有收到任何错误或输出什么。
输入的数据应该进入列表，输入的索引应该从列表中删除。
#!/usr/bin/env python3
#class definitions
class record:
def __init__(self,telephone,lastname,firstname):
self.telephone = telephone
self.lastname = lastname
self.firstname = firstname
def __str__(self):
return f"Last name: {self.lastname}, First Name: {self.firstname}, Telephone: {self.telephone}"
class PhoneBook:
def __init__(self):
self.phonebook = []
def addrecord(self, record):
self.phonebook.append(record)
return self.phonebook.index(record)
def deleterecord(self, i):
self.phonebook.pop(i-1)
def printphonebook(self):
x = 1
for entry in self.phonebook:
print(x,'. ',entry,sep='')
x = x + 1
#Main
select = None
while select != 'exit':
ph = PhoneBook()
ph.addrecord(record(515,'fin','matt'))
ph.addrecord(record(657,'fisher','bill'))
select = input('Main Menu \n1. show phonebook \n2. add record \n3. remove record\nor "exit" to exit program\n')
test = False
while test == False:
if select == '1':
ph.printphonebook()
test = True
elif select == '2':
x = int(input('Enter telephone number.\n'))
y = str(input('Enter last name.\n'))
z = str(input('Enter first name.\n'))
ph.addrecord(record(x,y,z))
test = True
elif select == '3':
i = int(input('Enter the record number youd like to delete.\n'))
ph.deleterecord(i)
test = True
elif select == 'exit':
break
else:
print('Invalid selection. Please try again.')
test = True
所需的输出将是让数据根据我的 x、y 和 z 输入正确进入和退出列表，并根据 i 输入取出列表的指定索引。