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想要使用 AWS Secrets manager 登录 postgres 而不使用用户名和密码作为纯文本。我不确定这是否可行，如果不可行，请原谅我。目前，这是我使用 psycopg2 登录到 postgres 的方法：

 import psycopg2

conn = psycopg2.connect(host="hostname",port='5432',database="db", user="admin", password="12345")

我已经将用户名和密码存储在秘密管理器中，但不知道如何在这里使用它。请帮忙

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2 回答 2

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您可以使用控制台将您的凭证（用户名/密码）存储在 SecretsManager 中。您可以将它们存储为键值对，例如 -

{ "username": "admin", "password": "12345" }

要在您的 Python 脚本中使用它，您可以执行以下操作 -

session = boto3.session.Session()
client = session.client(
    service_name='secretsmanager',
    region=< region_name >
)
secret = client.get_secret_value(
         SecretId=secret_name
)
secret_dict = json.loads(secret['SecretString'])

username = secret_dict['username']
passw = secret_dict['password']

conn = psycopg2.connect(host="hostname",port='5432',database="db", user=username, password=passw)

请注意，这是一个没有错误处理的简化示例。您还需要填写正确的区域来代替示例中的 <region_name>。

于 2019-05-01T22:09:12.527 回答
0

您应该使用以下过程：

  1. 连接到 AWS 机密管理器。
  2. 检索用户名和密码。您需要按照您在机密管理器中存储的方式对其进行映射。
  3. 将其存储在变量中并将其传递给连接字符串。

以下是amazon提供的示例 python 脚本：

import boto3
import base64
from botocore.exceptions import ClientError


def get_secret():

    secret_name = "<<{{MySecretName}}>>"
    region_name = "<<{{MyRegionName}}>>"

    # Create a Secrets Manager client
    session = boto3.session.Session()
    client = session.client(
        service_name='secretsmanager',
        region_name=region_name
    )

    # In this sample we only handle the specific exceptions for the 'GetSecretValue' API.
    # See https://docs.aws.amazon.com/secretsmanager/latest/apireference/API_GetSecretValue.html
    # We rethrow the exception by default.

    try:
        get_secret_value_response = client.get_secret_value(
            SecretId=secret_name
        )
    except ClientError as e:
        if e.response['Error']['Code'] == 'DecryptionFailureException':
            # Secrets Manager can't decrypt the protected secret text using the provided KMS key.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InternalServiceErrorException':
            # An error occurred on the server side.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InvalidParameterException':
            # You provided an invalid value for a parameter.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InvalidRequestException':
            # You provided a parameter value that is not valid for the current state of the resource.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'ResourceNotFoundException':
            # We can't find the resource that you asked for.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
    else:
        # Decrypts secret using the associated KMS CMK.
        # Depending on whether the secret is a string or binary, one of these fields will be populated.
        if 'SecretString' in get_secret_value_response:
            secret = get_secret_value_response['SecretString']
        else:
            decoded_binary_secret = base64.b64decode(get_secret_value_response['SecretBinary'])

    # Your code goes here.
于 2019-05-01T08:52:43.007 回答