1

基本上我正在尝试构建转发电子邮件，然后将其转换为 EML 文件。但原始消息对象msg呈现为附件而不是EML文件中的普通消息。我已经尝试过 将它添加到多部分电子邮件中的方法，但没有运气setContent。getDataHandler如果有人能帮助我解决这个问题，我真的很感激。

PSmsg对象的实际内容是text/html格式而不是text/plain.

谢谢。 

       MimeMessage forward = new MimeMessage(mailSession);

          // Fill in header
          forward.setSubject("Fwd: " + msg.getSubject());
          forward.setFrom(new InternetAddress(from));
          forward.addRecipient(Message.RecipientType.TO,new InternetAddress("toemail@ibm.com")); 
          forward.addRecipient(Message.RecipientType.CC,new InternetAddress("ccemail@gmail.com"));  


          // Create your new message part
            MimeBodyPart messageBodyPart = new MimeBodyPart();
            messageBodyPart.setContent(
                      "<html><body><h1>This is actual message embedded in HTML tags</h1></body></html>",
                     "text/html");

          // Create a multi-part to combine the parts
            MimeMultipart multipart = new MimeMultipart();
          multipart.addBodyPart(messageBodyPart);

          // Create and fill part for the forwarded content
          messageBodyPart = new MimeBodyPart();
          messageBodyPart.setDataHandler(msg.getDataHandler());
          //messageBodyPart.setContent(msg, "message/rfc822");

          // Add part to multi part
          multipart.addBodyPart(messageBodyPart);

          // Associate multi-part with message
          forward.setContent(multipart);



          // Send message
          Transport.send((Message)forward);
          System.out.println("message forwarded ....");
4

1 回答 1

1

当您将messageBodyPart集合Part::setDisposition添加到INLINE时。

 ...
 messageBodyPart = new MimeBodyPart();
 messageBodyPart.setDataHandler(msg.getDataHandler());
 messageBodyPart.setDisposition(Part.INLINE); //<-- Not an attachment.
 //messageBodyPart.setContent(msg, "message/rfc822");
 ...
于 2019-05-02T19:17:46.767 回答